Answer:
Step-by-step explanation:
9x9+6x8-6x+6=93
4x2+3x5-4x+3=11
93-11=82
the volume of the triangular prism will be, the area of the triangular face times its length
![\stackrel{\textit{area of the triangle}}{\left[ \cfrac{1}{2}(\underset{b}{8})(\underset{h}{8}) \right]}~~ ~~\stackrel{length}{(x)}~~ = ~~\stackrel{volume}{576}\implies 32(x)=576 \\\\\\ 32x=576\implies x=\cfrac{576}{32}\implies x=18](https://tex.z-dn.net/?f=%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20triangle%7D%7D%7B%5Cleft%5B%20%5Ccfrac%7B1%7D%7B2%7D%28%5Cunderset%7Bb%7D%7B8%7D%29%28%5Cunderset%7Bh%7D%7B8%7D%29%20%5Cright%5D%7D~~%20~~%5Cstackrel%7Blength%7D%7B%28x%29%7D~~%20%3D%20~~%5Cstackrel%7Bvolume%7D%7B576%7D%5Cimplies%2032%28x%29%3D576%20%5C%5C%5C%5C%5C%5C%2032x%3D576%5Cimplies%20x%3D%5Ccfrac%7B576%7D%7B32%7D%5Cimplies%20x%3D18)
Answer:
The statement is false.
Step-by-step explanation:
A parallelogram is a figure of four sides, such that opposite sides are parallel
A rectangle is a four-sided figure such that all internal angles are 90°
Here, the statement is:
"A rectangle is sometimes a parallelogram but a parallelogram is always a
rectangle."
Here if we found a parallelogram that is not a rectangle, then that is enough to prove that the statement is false.
The counterexample is a rhombus, which is a parallelogram that has two internal angles smaller than 90° and two internal angles larger than 90°, then this parallelogram is not a rectangle, then the statement is false.
The correct statement would be:
"A parallelogram is sometimes a rectangle, but a rectangle is always a parallelogram"
