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Veseljchak [2.6K]
3 years ago
10

A device for acclimating military pilots to the high accelerations they must experience consists of a horizontal beam that rotat

es horizontally about one end while the pilot is seated at the other end. In order to achieve a radial acceleration of 34.1 m/s2 with a beam of length 5.55 m , what rotation frequency is required?
Physics
1 answer:
vladimir2022 [97]3 years ago
6 0

Answer:

f = 0.4 Hz

Explanation:

The frequency of rotation of an object in order to achieve required centripetal or radial acceleration, can be found out by using the following formula:

f = (1/2π)√(ac/r)

where,

f = frequency of rotation = ?

ac = radial acceleration = 34.1 m/s²

r = radius = length of beam = 5.55 m

Therefore,

f = (1/2π)√[(34.1 m/s²)/(5.55 m)]

<u>f = 0.4 Hz</u>

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An electromagnetic wave in a vacuum traveling in the +x direction generated by a variable source initially has a wavelength λ of
djverab [1.8K]

Answer:

B = E/c = 14.04T₁ = 11 pT

Explanation:

We know c = E/B where E = maximum electric field = 3.30 × 10⁻³ V/m, B = maximum magnetic field and c = speed of light

B = E/c also c = fλ = λ/T where λ = wavelength = 235 μm = 235 × 10⁻⁶ m and T = period

c = λ₁/T₁ = λ₂/T₂    T₂ = 2.8T₁ where λ₁,λ₂ are the initial and final wavelengths and T₁,T₂ are the initial and final periods.

T₁ =  λ₁/c = 235 × 10⁻⁶ m/3 × 10⁸ m/s = 7.833 × 10⁻¹³ s = 0.7833 ps

T₂ = 2.8T₁ = 2.8 × 7.833 × 10⁻¹³ s = 21.93 × 10⁻¹³ s = 2.193 ps

λ₁/T₁ = λ₂/2.8T₁

λ₂ = 2.8λ₁ = 2.8 × 235 μm = 658 μm

c = λ₂/T₂ = 2.8λ₁/2.8T₁ = λ₁/T₁ , since the speed of light c is constant.

B = E/c = E/λ₁/T₁ = ET₁/λ₁

B = ET₁/λ₁ = 3.30 × 10⁻³ V/m × T₁/235 × 10⁻⁶ m = 14.04T₁  Tesla

B = 14.04 × 7.833 × 10⁻¹³ s = 10.99 × 10⁻¹² T ≅ 11 pT

5 0
4 years ago
On which factors does friction depend ?​
goldenfox [79]

Answer:

It depends on 2 factors

the nature of the materials

the normal force.

Explanation:

It depends on 2 factors

the nature of the materials that are in friction and the treatment that they have followed. This factor is expressed by a numerical value called the coefficient of friction or friction.

the force exerted by one body on the other, that is, the normal force.

3 0
3 years ago
students make a small elevator machine with 5 kg and 10 kg masses on either side how fast will the masses accelerate once they a
mihalych1998 [28]

Answer:

The acceleration of the elevator machine is, a = 3 m/s²                

Explanation:

Given data,

The mass on the one end, m = 5 kg

The mass on the other end, M = 10 kg

According to the Atwood's machine

                    Ma = Mg - T

                     ma = T - mg

Adding those equations,

                   a (M + m) = g ( M - m)

                       a = (M + m) / ( M - m)

Substituting the values,

                       a = (10 + 5) / (10 - 5)

                          = 3 m/s²

The acceleration of the elevator machine is, a = 3 m/s²                

8 0
3 years ago
When the sphere makes a complete revolution around its circular path, does it spend:_______
topjm [15]

Answer:

Explanation:

the same amount of time in both halves of the circle

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One mole of a substance contains 6.02 × 1023 protons and an equal number of electrons. If the protons could somehow be separated
Aleksandr [31]

Explanation:

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