Answer:
The velocity of the ball is 0.92 m/s in the downward direction (-0.92 m/s).
Explanation:
Hi there!
The equation for the velocity of an object thrown upward is the following:
v = v0 + g · t
Where:
v = velocity of the ball.
v0 = initial velocity.
g = acceleration due to gravity (-9.8 m/s² considering the upward direction as positive).
t = time.
To find the velocity of the ball at t = 0.40 s, we have to replace "t" by 0.40 s in the equation:
v = v0 + g · t
v = 3.0 m/s - 9.8 m/s² · 0.40 s
v = -0.92 m/s
The velocity of the ball is 0.92 m/s in the downward direction (-0.92 m/s).
An 'alpha particle' is the same thing as the nucleus of a helium atom ...
a little bundle made of 2 protons and 2 neutrons.
A 'beta' particle is an electron.
The mass of an alpha particle is more than 7,000 times the mass of
an electron, so it certainly takes more energy to get it moving.
The number of kilowatts used by an individual to operate his appliances is determined as 12.1 kWh.
<h3>
Average daily power consumption</h3>
The average daily power consumption is the amount of electric energy consumed by an individual on a daily rate.
The average daily power consumption of individuals in USA is 12,100 W-hr.
<h3>Converting watts to kilowatts</h3>
E = 12,100 Whr/1000
E = 12.1 kWh
Thus, the number of kilowatts used by an individual to operate his appliances is determined as 12.1 kWh.
Learn more about power here: brainly.com/question/13881533
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The bullet travels a horizontal distance of 276.5 m
The bullet is shot forward with a horizontal velocity 
. It takes a time <em>t</em> to fall a vertical distance <em>y</em> and at the same time travels a horizontal distance <em>x. </em>
The bullet's horizontal velocity remains constant since no force acts on the bullet in the horizontal direction.
The initial velocity of the bullet has no component in the vertical direction. As it falls through the vertical distance, it is accelerated due to the force of gravity.
Calculate the time taken for the bullet to fall through a vertical distance <em>y </em>using the equation,
Substitute 0 m/s for 
, 9.81 m/s²for <em>g</em> and 1.5 m for <em>y</em>.
The horizontal distance traveled by the bullet is given by,
Substitute 500 m/s for and 0.5530s for t.
The bullet travels a distance of 276.5 m.
To solve the problem it is necessary to apply the concepts related to Force of Friction and Tension between the two bodies.
In this way,
The total mass of the cars would be,
Therefore the friction force at 29Km / h would be,
In this way the tension exerts between first car and locomotive is,
Therefore the tension in the coupling between the car and the locomotive is 
