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77julia77 [94]
3 years ago
14

you press on the cqartiod ortery in your neck and begin counting . what are you mostly likely measuring?

Physics
1 answer:
Sladkaya [172]3 years ago
5 0
You are measuring your pulse rate.
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A tennis ball is tossed upward with a speed of 3.0\,\dfrac{\text m}{\text s}3.0 s m ​ 3, point, 0, start fraction, start text, m
MrRa [10]

Answer:

The velocity of the ball is 0.92 m/s in the downward direction (-0.92 m/s).

Explanation:

Hi there!

The equation for the velocity of an object thrown upward is the following:

v = v0 + g · t

Where:

v = velocity of the ball.

v0 = initial velocity.

g = acceleration due to gravity (-9.8 m/s² considering the upward direction as positive).

t = time.

To find the velocity of the ball at t = 0.40 s, we have to replace "t" by 0.40 s in the equation:

v = v0 + g · t

v = 3.0 m/s - 9.8 m/s² · 0.40 s

v = -0.92 m/s

The velocity of the ball is 0.92 m/s in the downward direction (-0.92 m/s).

8 0
3 years ago
Read 2 more answers
Why should it take significantly more energy to move a beam of alpha particles than a beam of beta minus (β–) particles?
a_sh-v [17]
An 'alpha particle' is the same thing as the nucleus of a helium atom ... 
a little bundle made of 2 protons and 2 neutrons.

A 'beta' particle is an electron.

The mass of an alpha particle is more than 7,000 times the mass of 
an electron, so it certainly takes more energy to get it moving.
4 0
3 years ago
Read 2 more answers
Part B
Licemer1 [7]

The number of kilowatts used by an individual to operate his appliances is determined as 12.1 kWh.

<h3>Average daily power consumption</h3>

The average daily power consumption is the amount of electric energy consumed by an individual on a daily rate.

The average daily power consumption of individuals in USA is 12,100 W-hr.

<h3>Converting watts to kilowatts</h3>

E = 12,100 Whr/1000

E = 12.1 kWh

Thus, the number of kilowatts used by an individual to operate his appliances is determined as 12.1 kWh.

Learn  more about power here: brainly.com/question/13881533

#SPJ1

5 0
2 years ago
A gun shoots a bullet with a velocity of 500 m/s. The gun is aimed horizontally and fired from a height of 1.5 m. How far does t
MrMuchimi

The bullet travels a horizontal distance of 276.5 m

The bullet is shot forward with a horizontal velocity u_x. It takes a time <em>t</em> to fall a vertical distance <em>y</em> and at the same time travels a horizontal distance <em>x. </em>

The bullet's horizontal velocity remains constant since no force acts on the bullet in the horizontal direction.

The initial velocity of the bullet has no component in the vertical direction. As it falls through the vertical distance, it is accelerated due to the force of gravity.

Calculate the time taken for the bullet to fall through a vertical distance <em>y </em>using the equation,

y=u_yt+\frac{1}{2} gt^2

Substitute 0 m/s for u_y, 9.81 m/s²for <em>g</em> and 1.5 m for <em>y</em>.

y=u_yt+\frac{1}{2} gt^2\\ 1.5 m=(0m/s)t+\frac{1}{2} (9.81m/s^2)t^2\\ t=\sqrt{\frac{2(1.5m)}{9.81m/s^2} } =0.5530s

The horizontal distance traveled by the bullet is given by,

x=u_xt

Substitute 500 m/s for u_x and 0.5530s for t.

x=u_xt\\ =(500m/s)(0.5530s)\\ =276.5m

The bullet travels a distance of 276.5 m.


5 0
3 years ago
A locomotive accelerates a 25-car train along a level track. Every car has a mass of 7.7 ✕ 104 kg and is subject to a friction f
MaRussiya [10]

To solve the problem it is necessary to apply the concepts related to Force of Friction and Tension between the two bodies.

In this way,

The total mass of the cars would be,

m_T = 25(7.7*10^4)Kg

m_T = 1.925*10^6Kg

Therefore the friction force at 29Km / h would be,

f=250v

f= 250*29Km/h

f = 250*29*(\frac{1000m}{1km})(\frac{1h}{3600s})

f = 2013.889N

In this way the tension exerts between first car and locomotive is,

T=m_Ta+f

T=(1.925*10^6)(0.2)+2013.889

T= 3.8701*10^5N

Therefore the tension in the coupling between the car and the locomotive is 3.87*10^5N

6 0
3 years ago
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