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ryzh [129]
3 years ago
8

Solve the system of equations and choose the correct ordered pair. 3x + 4y = 38 5x - 5y = -30

Mathematics
1 answer:
faust18 [17]3 years ago
3 0
3x + 4y = 38 ( equation 1) ----> ×5 5x - 5y = -30 ( equation 2) ----> ×3 When you multiply eqn 1 by 5 you get, 15x + 20y = 190 And when you multiply eqn 2 by 3, you get, 15x - 15y = -90 Then you solve both equations by subtracting eqn 2 from eqn 1 15x + 20y = 190 15x - 15y = 90 Then 15x - 15x gets cancelled and 20y - (-15y) gives 35y and 190 - (-90) gives 280. So that gives 35y = 280 y = 8 And when you replace y = 8 in any of the two equations, x = 2
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The formula for the perimeter of a rectangle with the length and the width is given above. If a rectangle has perimeter 24, what
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Explanation:
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Find the volume of this right rectangular prism. [type your answer as a number]
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Answer:

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Step-by-step explanation:

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Hhelp pls lol i don't understand​
sladkih [1.3K]

Answer:

m∠1= 80

m∠2= 100

m∠3= 80

Step-by-step explanation:

Given: m∠1= 2x +40

m∠2= 2y +40

m∠3= x +2y

m∠1 +m∠2= 180 (adj. ∠s on a str. line)

2x +40 +2y +40= 180

2x +2y+ 80= 180

2x +2y= 180 -80

2x +2y= 100

2(x +y)= 100

x +y= 100 ÷2

x +y= 50 -----(1)

m∠1= m∠3 (vert. opp. ∠s)

2x +40= x +2y

2x -x +40= 2y

x= 2y -40 -----(2)

Substitute equation (2) into (1):

2y -40 +y= 50

3y= 50 +40

3y= 90

y= 90 ÷3

y= 30

Substitute y= 30 into equation (2):

x= 2(30) -40

x= 60 -40

x= 20

m∠1

= 2x +40

= 2(20) +40

= 40 +40

= 80

m∠2

= 2y +40

= 2(30) +40

= 60 +40

= 100

m∠3

= x +2y

= 20 +2(30)

= 20 +60

= 80

Alternatively, since m∠1= m∠3,

m∠3

= m∠1 (vert. opp. ∠s)

= 80

5 0
3 years ago
Can someone please help me with these problems. Thank you
grin007 [14]
P(3) = 1/6
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P(less than 5) = 4/6 = 2/3.....(less than 5: 1,2,3,4)
P(prime) = 3/6 = 1/2 ..........(prime: 2,3,5)
P(4 or 6) = 2/6 = 1/3
P(not 1) = 5/6 .....................(not 1: 2,3,4,5,6)

hope it helps
6 0
3 years ago
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