3. Which situation could be represented by the graph shown?

Mathematics

1 answer:

Law Incorporation [45]3 years ago

5 0

Answer:sophia

Step-by-step explanation:

You might be interested in

Plz help me with this

Contact [7]

The answer is (A) $-18p^{5}-30p^{4}+6p^{3}$

8 0

3 years ago

Read 2 more answers

Lines MN and PQ are parallel. Lines RS and TV intersect them. Which statements are true about these lines? Check all that apply.

Maru [420]

The correct answer is: 
RS is perpendicular to MN and PQ.

Explanation: 
We can use the slopes of these lines to determine the answer.
Slope is given by the formula 
m= $\frac{y_{2}- y_{1} }{ x_{2} - x_{1} }$ .

Using the coordinates for M and N, we have: 
m= $\frac{3--1}{3--3} = \frac{4}{6} = \frac{2}{3}$ .

Since PQ is parallel to MN, its slope will be $\frac{2}{3}$ as well, since parallel lines have the same slope.

Using the coordinates for points T and V in the slope formula, we have 
m= $\frac{-4-1}{0--4} =- \frac{5}{4}$ .

This is not parallel to MN or PQ, since the slopes are not the same.
We can also say that it is not perpendicular to these lines; perpendicular lines have slopes that are negative reciprocals (they are opposite signs and are flipped). This is not true of TV either.

Using the coordinates for R and S in the slope formula, we have 
m= $\frac{-2-1}{2-0} =- \frac{3}{2}$ . Comparing this to the slope of RS, it is flipped and the sign is opposite; they are negative reciprocals, so they are perpendicular.