Ask question

Ask question

All categories

3 years ago

7

Kim is planning a trip to Spain. She will stay there for a total of thirteen nights. She has found two options for her lodging:

a hostel, which charges €12.65 (12.65 euros) per night, and a private hotel, which charges €31.25 per night. Kim would like to spend as many nights as she can afford in the private hotel. If she has a budget of €275 for lodging, how many nights can she stay in the hotel? a. four b. five c. six d. seven

1 answer:

lys-0071 [83]3 years ago

3 0

Answer:

5

Step-by-step explanation:

search up your answer and its on a quizlet

You might be interested in

Solve. i really need help<br><br><br><br> z =

BlackZzzverrR [31]

$\dfrac{7z-1}{2}=3z-2\\
7z-1=6z-4\\
7z-6z=-4+1\\
z=-3$

5 0

3 years ago

The perimeter of a rectangle is 154 feet. The length of the rectangle is 55 feet. What is the width of the rectangle?

alisha [4.7K]

Hi there! Okay well to find out the width when you all ready have the perimeter and length just add up both sides of the length, 55+55=110 okay now just subtract 110 from 154, 154-110=44 now since there are to sides for width in a rectangle divide 44 by 2, 44÷2=22 so your width is 22 now to check add up all your side's: 55+22+55+22=154 ANSWER: width = 22ft

3 0

3 years ago

Read 2 more answers

Find an ordered pair (x,y) that is a solution to the equation. 3x-y=8

allochka39001 [22]

Answer:

(2,-2)

Step-by-step explanation:

$3x-y =3(2) -(-2)= 6 +2 = 8$

7 0

3 years ago

(Anderson, 1.14) Assume that P(A) = 0.4 and P(B) = 0.7. Making no further assumptions on A and B, show that P(A ∩ B) satisfies 0

Goshia [24]

Answer with Step-by-step explanation:

We are given that

P(A)=0.4 and P(B)=0.7

We know that

$P(A)+P(B)+P(A\cap B)=P(A\cup B)$

We know that

Maximum value of $P(A\cup B)$ =1 and minimum value of $P(A\cup B)$ =0

$0\leq P(A\cup B )\leq 1$

$0\leq P(A)+P(B)-P(A\cap B)\leq 1$

$0\leq 0.4+0.7-P(A\cap B)\leq 1$

$0\leq 1.1-P(A\cap B)\leq 1$

$0\leq 1.1-P(A\cap B)$

$P(A\cap B)\leq 1.1$

It is not possible that $P(A\cap B)$ is equal to 1.1

$1.1-P(A\cap B)\leq 1$

$-P(A\cap B)\leq 1-1.1=-0.1$

Multiply by (-1) on both sides

$P(A\cap B)\geq 0.1$

Again, $P(A\cup B)\geq P(B)$

$0.4+0.7-P(A\cap B)\geq 0.7$

$1.1-P(A\cap B)\geq 0.7$

$-P(A\cap B)\geq -1.1+0.7=-0.4$

Multiply by (-1) on both sides

$P(A\cap B)\leq 0.4$

Hence, $0.1\leq P(A\cap B)\leq 0.4$

3 0

3 years ago

I have these fractions: 4/5 , 5/6 , and 3/12. Can someone help to put them in order from LEAST to GREASTEST?

vodomira [7]

The answer is 5/6, 4/5, and 3/12. All you needed to do was change the fraction into decimals.

5 0

3 years ago