K = ln (153/147)/7
k =
<span>
ln
(<span>
<span>
1.0408163265)/7
k = </span></span></span>0.040005334584
y(t) = a * e ^ k*t
y(2017) = 147 * e^ <span><span><span>0.040005334584
</span>
</span>
</span>
* 26
y(2017) = 147*e^
<span>
<span>
<span>
1.0401386992
</span>
</span>
</span>
y(2017) = 147*
<span>
<span>
<span>
2.8296094512
</span>
</span>
</span>
<span>y(2017) = 415.95 NOT very sure of that answer
</span>
Answer:
2/3
Step-by-step explanation:
If we have 'x' students who like math and 'y' students that like science, we can formulate that:
Half of x likes math and science, and also one third of y likes math and science, so:
(1/2) * x = (1/3) * y
x / y = (1/3) / (1/2)
x / y = (1/3) * 2 = 2/3
So the ratio of the number of students who like math to the number of students who like science is 2/3
Answer:
GCF= 1
LCM= 1680
Step-by-step explanation:
GCF= Find the prime factorization of 21, 21 = 3 x 7
Find the prime factorization of 80, 80 = 2 x 2 x 2 x 2 x 5
Then multiply the prime factors both numbers have in common
LCM= multiply the two numbers together and ignore all negative signs
Without any calculations it's evident it can't be neither B (both numbers are even, so they're divisible by 2) nor C (the numbers end in 0 and 5, so they're divisible by 5).
A.
Both numbers have a factor of 3, so they're not relatively prime.
That means it must be D. But, let's check it.
Indeed, those two numbers are relatively prime.
