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nirvana33 [79]
3 years ago
15

Shobos mother present age is six times shobos present age. Shobos age five from now will be one third of his mother's present ag

e. What are their present ages ?
Mathematics
2 answers:
r-ruslan [8.4K]3 years ago
5 0

Answer:

Step-by-step explanation:

From the problem statement, we can setup the following equations:

M = 6S

S + 5 = \frac{1}{3}M

where S is the current age of Shobos and M is the current age of his mother.

Substituting the first equation into the second will allow us to solve for S:

S + 5 = \frac{1}{3}M

S + 5 = \frac{1}{3}(6S)

S + 5 = 2S

S = 5

Substituting this value into the first equation gives us the age of the mother:

M = 6S

M = 6(5)

M = 30

AveGali [126]3 years ago
4 0

Answer:

Present age of Shobo is 5 years and present age of Shobo's mother is 30 years.

Step-by-step explanation:

<u>Give</u><u>n</u><u> </u><u>:</u><u>-</u>

  • Shobo's mother's present age is 6 times of Shobo's present age.
  • Shobo's age 5 from now will be 1/3 of his mother's present age.

<u>T</u><u>o</u><u> </u><u>find</u><u> </u><u>:</u><u>-</u>

  • Their present ages.

<u>Solu</u><u>tion</u><u> </u><u>:</u><u>-</u>

Consider,

  • Shobo's present age = x years

★ Shobo's mother's present age is 6 times of Shobo's present age.

  • Shobo's Mother's Present age = 6x years

Shobo's age 5 from now,

= (x+5) years

<u>Acco</u><u>rding</u><u> to</u><u> the</u><u> </u><u>que</u><u>stion</u><u> </u><u>,</u>

\to\sf{x+5=\dfrac{1}{3}\times\:6x}

→ x + 5 = 2x

→ x-2x = -5

→ -x = -5

→ x = 5

★ Shobo's present age = 5 years

★ Shobo's mother's present age = 6×5 = 30 years.

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