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3 years ago

15

John rode 4 kilometers on his bike his sister sally rode 3400 meters on her bike who rode the farthest and how much farther did

they ride

1 answer:

emmasim [6.3K]3 years ago

7 0

4 kilometres is 4000 meters

4000 meters - 3400 meters = 600 meters

and as John is the one that rode 4 kilometres he rode further and by 600 meters

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-2(x+3y)=18 solve for y!

jeka94

$-2(x+3y)=18\ \ \ \ /:(-2)\\\\x+3y=9\\\\3y=9-x\ \ \ \ /:3\\\\y=\frac{9-x}{3}\\\\y=\frac{9}{3}-\frac{x}{3}\\\\y=3-\frac{1}{3}x\\\\y=-\frac{1}{3}x+3$

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3 years ago

Read 2 more answers

What is the radian measure of a 150° angle?

jolli1 [7]

Well, since we know that in π radians there are 180°, then how many radians in 150°?

$\bf \begin{array}{ccll}
radians&de grees\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
\pi &180\\
x&150
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8 0

3 years ago

For many years businesses have struggled with the rising cost of health care. But recently, the increases have slowed due to les

kaheart [24]

Answer:

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The margin of error for this case is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259$

And replacing into the confidence interval formula we got:

$0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941$

$0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459$

And the 95% confidence interval would be given (0.4941;0.5459).

Step-by-step explanation:

Data given and notation

n=1000 represent the random sample taken

$\hat p=0.52$ estimated proportion of of U.S. employers were likely to require higher employee contributions for health care coverage

$\alpha=0.05$ represent the significance level (no given, but is assumed)

Solution to the problem

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The margin of error for this case is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259$

And replacing into the confidence interval formula we got:

$0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941$

$0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459$

And the 95% confidence interval would be given (0.4941;0.5459).

5 0

2 years ago

What is the unit rate of 3.5 miles in 1.25 hours

snow_lady [41]

3.5 miles / 1.25 hours = 2.8 mph

3 0

3 years ago

A 16-ounce bottle of orange juice says it contains 200 milligrams of vitamin C, which is 250% of the daily recommended allowance

iren2701 [21]

Answer:

100% of the daily recommended allowance of vitamin C for adults is 80 milligrams.

Step-by-step explanation:

A 16-ounce bottle of orange juice says it contains 200 milligrams of vitamin C, which is 250% of the daily recommended allowance of vitamin C for adults.

100% will have = $\frac{200}{250}\times100$ = 80 milligrams

Hence, 100% of the daily recommended allowance of vitamin C for adults is 80 milligrams.

8 0

3 years ago