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disa [49]
3 years ago
13

Compute the probability of rolling a 12 sided die and getting a number other than 8. please help​

Mathematics
1 answer:
sammy [17]3 years ago
6 0
11/12 ≈ 0.916
chance of getting a number other than 8
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Use a while loop to determine how many terms in the series 3k^2 are required for the sum to surpass 2000
Bumek [7]
Using JAVA:
int sum = 0;       
int k = 1;       
while(sum  <= 2000) {           
sum += 3*k*k;           
 k++;       
 }               
System.out.println(k);

Output: 14

Which means it will take 14 terms for the series to surpass 2000


6 0
4 years ago
Read 2 more answers
Please help!
Kobotan [32]

Answer:

You have three card : 3, 4, and 5.

You first pick one card randomly, the probability of picking a 3 is:

P = 1/3

You then pick a second card without putting the first card back, the probability of picking a 5 is:

P = 1/2

=> The probability of picking a 3 and then picking a 5:

P = (1/3) x (1/2) = 1/6

Hope this helps!

:)

8 0
3 years ago
PQRS is a parallelogram of area 18 cm. if PQ = 5 cm &amp; QR = 4 cm. calculate the lengths of corresponding heights ?​
kupik [55]

Answer:

2cm

Step-by-step explanation:

area of parallelogram=b*h=18cm

5*4=20

length of corresponding heights=20-18

=2cm

3 0
3 years ago
HELP WILL MARK BRAINLIEST!!!
Alenkasestr [34]

Answer:

y = 12

Step-by-step explanation:

set up equation for 'y varies inversely with x':  y = k/x

where 'k' is the constant of variation

8 = k/6

therefore, k = 48

value of y when x = 4:  y = 48/4; therefore, y = 12

                     

7 0
3 years ago
Each spinner below is spun. Find the probability.
sveta [45]

Answer: the answer is B1/17

Step-by-step explanation:

8 0
3 years ago
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