Most likely you are expected to recognize that side lengths 2, 3, 5 will result in a "triangle" of zero area (looks like a line segment).
The appropriate choice is
(5, 3, 2)
_____
Some authors write the triangle inequality as a + b ≥ c for any assignment of a, b, c to side lengths. The "or equal to ..." allows the triangle to have zero area (looks like a line segment). Other authors insist the inequality not include the "or equal to" case. It looks like your text's author is in the latter camp.
A) zeroes
P(n) = -250 n^2 + 2500n - 5250
Extract common factor:
P(n)= -250 (n^2 - 10n + 21)
Factor (find two numbers that sum -10 and its product is 21)
P(n) = -250(n - 3)(n - 7)
Zeroes ==> n - 3 = 0 or n -7 = 0
Then n = 3 and n = 7 are the zeros.
They rerpesent that if the promoter sells tickets at 3 or 7 dollars the profit is zero.
B) Maximum profit
Completion of squares
n^2 - 10n + 21 = n^2 - 10n + 25 - 4 = (n^2 - 10n+ 25) - 4 = (n - 5)^2 - 4
P(n) = - 250[(n-5)^2 -4] = -250(n-5)^2 + 1000
Maximum ==> - 250 (n - 5)^2 = 0 ==> n = 5 and P(5) = 1000
Maximum profit =1000 at n = 5
C) Axis of symmetry
Vertex = (h,k) when the equation is in the form A(n-h)^2 + k
Comparing A(n-h)^2 + k with - 250(n - 5)^2 + 1000
Vertex = (5, 1000) and the symmetry axis is n = 5.
Answer:
in 13.95 years the senior class will have 100 students.
Step-by-step explanation:
P(h) = p(0.92)^t (equation for exponential change)
P(h) - population of highschool (or senior class) = 100
p - staring amount = 320
t = time in years
100 = 320(0.92)^t
1/3.2 = .92^t (divide both sides by 320)
log(1/3.2, .92) = t (log base 0.92 of 1/3.2 equals t)
13.9497 = t
I’m going to go with 77 i’m pretty sure
