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3 years ago

14

Look at each pattern.

1 answer:

gulaghasi [49]3 years ago

6 0

Answer:

pattern A is going by 3

pattern B is going by 12

Step-by-step explanation:

so you basically just have to add 3 for pattern a and add 12 for pattern B for each number

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Which statement is true?

lutik1710 [3]

2nd one, hope this helps sorry if i am wrong

3 0

3 years ago

Read 2 more answers

Can u pls help I don’t understand I’ll give u 15 points

Juliette [100K]

Answer: $\frac{4}{3}$

Step-by-step explanation:

This is a multiplication problem. You are multiplying $\frac{1}{3}$ by 4. This also means 4 divided by 3. They are both the same.

4 0

3 years ago

Some one help me ASAP

Marrrta [24]

Answer:

The measure of the angle ABD is:

m∠ABD = 122°

Step-by-step explanation:

Given

m∠ABC = 84°

m∠CBD = 38°

To determine

Find m∠ABD

The given diagram shows that m∠ABD is the sum of m∠ABC and m∠CBD.

In other words,

m∠ABD = m∠ABC + m∠CBD

substituting m∠ABC = 84° and m∠CBD = 38°

m∠ABD = 84° + 38°

m∠ABD = 122°

Therefore, the measure of the angle ABD is:

m∠ABD = 122°

8 0

3 years ago

Write an equation of a line in slope-intercept form given the slope (m) and the y- intercept (b), slope, m= -4/7 y-intercept b =

Leno4ka [110]

The answer is y=-4/7x+7. You simply substitute in the given numbers. -4/7 for the slope (m) and 7 for the y-intercept (b).

4 0

3 years ago

A box with a rectangular base and open top must have a volume of 128 f t 3 . The length of the base is twice the width of base.

noname [10]

Answer:

$Width = 4ft$

$Height = 4ft$

$Length = 8ft$

Step-by-step explanation:

Given

$Volume = 128ft^3$

$L = 2W$

$Base\ Cost = \$9/ft^2$

$Sides\ Cost = \$6/ft^2$

Required

The dimension that minimizes the cost

The volume is:

$Volume = LWH$

This gives:

$128 = LWH$

Substitute $L = 2W$

$128 = 2W * WH$

$128 = 2W^2H$

Make H the subject

$H = \frac{128}{2W^2}$

$H = \frac{64}{W^2}$

The surface area is:

Area = Area of Bottom + Area of Sides

So, we have:

$A = LW + 2(WH + LH)$

The cost is:

$Cost = 9 * LW + 6 * 2(WH + LH)$

$Cost = 9 * LW + 12(WH + LH)$

$Cost = 9 * LW + 12H(W + L)$

Substitute: $H = \frac{64}{W^2}$ and $L = 2W$

$Cost =9*2W*W + 12 * \frac{64}{W^2}(W + 2W)$

$Cost =18W^2 + \frac{768}{W^2}*3W$

$Cost =18W^2 + \frac{2304}{W}$

To minimize the cost, we differentiate

$C' =2*18W + -1 * 2304W^{-2}$

Then set to 0

$2*18W + -1 * 2304W^{-2} =0$

$36W - 2304W^{-2} =0$

Rewrite as:

$36W = 2304W^{-2}$

Divide both sides by W

$36 = 2304W^{-3}$

Rewrite as:

$36 = \frac{2304}{W^3}$

Solve for $W^3$

$W^3 = \frac{2304}{36}$

$W^3 = 64$

Take cube roots

$W = 4$

Recall that:

$L = 2W$

$L = 2 * 4$

$L = 8$

$H = \frac{64}{W^2}$

$H = \frac{64}{4^2}$

$H = \frac{64}{16}$

$H = 4$

Hence, the dimension that minimizes the cost is:

$Width = 4ft$

$Height = 4ft$

$Length = 8ft$

8 0

2 years ago