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Svetradugi [14.3K]
3 years ago
15

What is the square root of 12 simplified? Is it 2 times the square root of 3?

Mathematics
2 answers:
Mariulka [41]3 years ago
8 0

Answer:

Yes; 2\sqrt{3} . is correct.

Step-by-step explanation:

Remember that to find the simplified radical you must first break down the number given into its prime factors.

<em>prime factorization</em><em> of  12:  </em>2^2\cdot \:3.

So we have \sqrt{2^2\cdot \:3}. That can be written as \sqrt{2^2}\sqrt{3}.

\sqrt{2^{2}} = 2.

2 \: \cdot \: \sqrt{3} = 2\sqrt{3}.

Thusly, you are correct, it is 2\sqrt{3} .

Hope this helps! (:

blagie [28]3 years ago
4 0

Answer: Yes, it is 2\sqrt{3}

Step-by-step explanation:

To simplify square roots, you can factor the number inside the square root into its lowest common denominators.

\sqrt{12}=\sqrt{4*3}  =\sqrt{2*2*3}

Any value that appears twice can be "taken out" of the square root and moved to the left of it:

2\sqrt{3},

What you are doing is essentially taking the square root of 4 and the square root of 3. Because the square root of 4 can be simplified, and the square root of 3 cannot, this is the most simplified version of the expression we can reach.

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An exponential function is graphed on the grid
Lilit [14]

Answer:

a) the domain is the set of all real numbers

Step-by-step explanation:

Given:

An exponential function and its graph.

A line parallel to x axis is drawn at y=-9 which is a dashed line.

Dashed line means, the function does not attain a value equal to y=-9.

Domain of a function, y=f(x) is the set of values which can be possible for the variable x that can be given as input.

Range of a function, y=f(x) is the set of possible values of y i.e. the output of the function.

As seen from the graph, the domain of the exponential function does not have any constraint on it.

Therefore, any real number can be given as input.

So, <em>a) The domain is the set of all real numbers.</em>

<em></em>

Let us discuss about the range of function.

As stated above as well, the range of the function can not contain the value y=-9.

And there is no value possible below it.

So, the <em>range is all real numbers greater than -9.</em>

<em></em>

<em>The answer is:</em>

"a) the domain is the set of all real numbers"  is true.

3 0
3 years ago
Read 2 more answers
The price of Stock A at 9 A.M. was $14.04. Since then, the price has been increasing at the rate of $0.09 each hour. At noon the
saveliy_v [14]

Answer:

The price of Stock A at 9 A.M. was $14.04. Since then, the price has been increasing at the rate of $0.09 each hour. At noon the price of Stock B was $14.79. It begins to decrease at the rate of $0.07 each hour. If the two rates continue, in how many hours will the price of the two blocks be the same?

3 0
3 years ago
Fifteen tickets cost 193.75 what is the average cost of each ticket
zmey [24]
It is 13$ per one there
3 0
3 years ago
Factor completely 81x^8-1
marysya [2.9K]

The complete factorized form for the given expression is \left(9 x^{4}+1\right)\left(3 x^{2}+1\right)\left(3 x^{2}-1\right)

<u>Step-by-step explanation:</u>

Step 1: Given expression:

              81 x^{8}-1

Step 2: Trying to factor as a Difference of Squares

Factoring 81 x^{8}-1

As we know the theory that the difference of two perfect squares, A^{2}-B^{2}  can be factored into (A+B) (A-B)

from this, when analysing, 81 is the square of 9, x^{8} is the square of x^{4}. Hence, we can write the given expression as,

            \left(9 x^{4}\right)^{2}-1^{2}

By using the theory, we get

           \left(9 x^{4}+1\right)\left(9 x^{4}-1\right)

Again, we can further factorise the term \left(9 x^{4}-1\right)

9 x^{4} is the square of 3 x^{2}. Therefore, it can be expressed as below

           \left(3 x^{2}+1\right)\left(3 x^{2}-1\right)

Now, we can not factorise further the term \left(3 x^{2}-1\right). Because it will come as \sqrt{3} x (3 is not a square term). Thereby concluding that the complete factorisation for the given expression is \left(9 x^{4}+1\right)\left(3 x^{2}+1\right)\left(3 x^{2}-1\right)

8 0
4 years ago
What is 1.83 repeating as a fraction?
maks197457 [2]
The answer to this question would be: 1 5/6

To change a decimal number into fraction, you need to divide the number on the right of decimal point with 1. In this case, the number is 0.83.
This number is hard since .83 doesn't have many factors. To find the answer you can try to multiply the decimal with some number until it close to 1(no decimal left)
0.83* 2= 1.66
0.83* 3= 2.49 ---> close to half, if you find this number, you can try to double it
0.83* 4= 3.32
0.83* 5= 4.15
0.83* 6= 4.98---> close to 1, that means there is high probability that the number can be divided by 6 
0.83 would be 4.98/6, but if we assume that the number is 0.8333...... then 0.83 would be 5/6. So, 1.83 would be 1 5/6
4 0
3 years ago
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