Let's call n the number of days Marika's been training for the race, and
the distance she runs on the nth day in meters. After the first day, when n = 1, she runs 100 meters, so

On the second day, she runs an additional 4 meters, on the third day, another 4, and so on. Here's what that looks like mathematically:

It would be easier to write this continued addition as multiplication, in which case those same equations would look like

Notice that, in every case, the number 4 is being multiplied by is 1 less than n. We could even write for our first term that
. In general, we can say that

Which is expressed by option B.
(Bonus: What piece of information from this question did we not need to use here?)
Any points that are less than 6. So 5, 4, 3, 2, etc.
Answer:
4dogs and no wolves
Step-by-step explanation:
when a dog is taken care of (Trained) it could be let to run free in a definite region.
On a plane with one line we can place two dogs (one dog in each of the regions) and they will not fight as they will be separated by a line, and they will run free.
If we place three lines in general, then we would have four regions where 4 dogs can run free as they are separated by a line so as not to fight.
But for Wolves from the question it is deduced that: A wolf has to be caged all the time and no matter how well you train a wolve, it wont yield to instructions.
With these two, wolves wont be allowed on the plane at all.
Answer:

Step-by-step explanation:
Since this is a right triangle, we can use the Pythagorean Theorem to solve for the sides.

where <em>a</em> and<em> b</em> are the legs and <em>c</em> is the hypotenuse. In this triangle, we know the legs are 9 centimeters and 11 centimeters, or:
Substitute these values into the formula.

Solve the exponents.
- (9 cm)²= 9 cm*9 cm=81 cm²

- (11 cm)²= 11 cm*11 cm= 121 cm²

Add the values on the left side.

Since we are solving for c, we must isolate the variable. It is being squared and the inverse of a square is the square root. Take the square root of both sides.



We are told to round to the nearest tenth.
The 1 in the hundredth place tells us to leave the 2 in the tenth place.

The hypotenuse is equal to <u>14.2 centimeters.</u>
Answer:
15 inches
Step-by-step explanation:
We have that,
Length of the photo = 4 inches and Width of the photo = 6 inches
Also, the width of the image on the calendar = 10 inches
Let, the length on the image of the calendar = x inches.
Since, the ratio of the photo and its image will remain same, we get,

i.e. 
i.e. x = 15
Hence, the length of the image of the photo on the calendar is 15 inches.