If u help I’ll give u brainliest but please give correct answer

Please help. Marika is training for a race.

Anika [276]

Let's call n the number of days Marika's been training for the race, and $a_n$ the distance she runs on the nth day in meters. After the first day, when n = 1, she runs 100 meters, so

$a_1=100$

On the second day, she runs an additional 4 meters, on the third day, another 4, and so on. Here's what that looks like mathematically:

$a_2=100 + 4\\a_3=100 + 4 + 4\\a_4=100+4+4+4$

It would be easier to write this continued addition as multiplication, in which case those same equations would look like

$a_2 = 100 + 4(1)\\a_3 = 100 + 4(2)\\a_4=100+4(3)$

Notice that, in every case, the number 4 is being multiplied by is 1 less than n. We could even write for our first term that $a_1=100+4(0)$ . In general, we can say that

$a_n=100+4(n-1)$

Which is expressed by option B.

(Bonus: What piece of information from this question did we not need to use here?)

3 0

3 years ago

Help pls ill mark brainliest!!!!!!!!!!!!!!!!!

ziro4ka [17]

Any points that are less than 6. So 5, 4, 3, 2, etc.

8 0

2 years ago

Read 2 more answers

Suppose you have some wolves and some dogs. Dogs are named and wolves are not. If you call a dog it will run to you. A wolf woul

Ira Lisetskai [31]

Answer:

4dogs and no wolves

Step-by-step explanation:

when a dog is taken care of (Trained) it could be let to run free in a definite region.

On a plane with one line we can place two dogs (one dog in each of the regions) and they will not fight as they will be separated by a line, and they will run free.

If we place three lines in general, then we would have four regions where 4 dogs can run free as they are separated by a line so as not to fight.

But for Wolves from the question it is deduced that: A wolf has to be caged all the time and no matter how well you train a wolve, it wont yield to instructions.

With these two, wolves wont be allowed on the plane at all.

8 0

2 years ago

One of the legs of a right triangle measures 9 cm and the other leg measures 11 cm.

ikadub [295]

Answer:

$\boxed {\boxed {\sf 14.2 \ cm}}$

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean Theorem to solve for the sides.

$a^2+b^2=c^2$

where a and b are the legs and c is the hypotenuse. In this triangle, we know the legs are 9 centimeters and 11 centimeters, or:

a= 9 cm
b= 11 cm

Substitute these values into the formula.

$(9 \ cm)^{2} +(11 \ cm)^{2} =c^{2}$

Solve the exponents.

(9 cm)²= 9 cm*9 cm=81 cm²

$81 \ cm^{2} +(11 \ cm)^{2} =c^{2}$

(11 cm)²= 11 cm*11 cm= 121 cm²

$81 \ cm^{2} +121 cm^{2} =c^{2}$

Add the values on the left side.

$202 \ cm^{2} =c^{2}$

Since we are solving for c, we must isolate the variable. It is being squared and the inverse of a square is the square root. Take the square root of both sides.

$\sqrt {202 \ cm^{2} }=\sqrt{c^{2} }$