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zysi [14]
2 years ago
9

JKLM is a rhombus. KM is 10 and JL is 24. Find the perimeter of the rhombus.

Mathematics
1 answer:
Ahat [919]2 years ago
5 0
Given that JKLM is a rhombus and the length of diagonal KM=10 na d JL=24, the perimeter will be found as follows;
the length of one side of the rhombus will be given by Pythagorean theorem, the reason being at the point the diagonals intersect, they form a perpendicular angles;
thus
c^2=a^2+b^2
hence;
c^2=5^2+12^2
c^2=144+25
c^2=169
thus;
c=sqrt169
c=13 units;
thus the perimeter of the rhombus will be:
P=L+L+L+L
P=13+13+13+13
P=52 units

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2 years ago
At the movie theatre, child admission is $5.10 and adult admission is $9.70. On Thursday, 128 tickets were sold for a total sale
kvv77 [185]

Answer:

53

Step-by-step explanation:

Let x be the number of children tickets sold and y be the number of adult tickets sold. Then

x+y=128.

The cost of x children tickets is $5.10x and the cost of y adult tickets is $9.70y, so

5.10x+9.70y =896.60.

From the first equation,

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then

5.10(128-y)+9.70y=896.60,\\ \\652.80-5.10y+9.70y=896.60,\\ \\4.60y=243.8,\\ \\y=53.

53 adult tickets were sold.

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3 years ago
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