Given that JKLM is a rhombus and the length of diagonal KM=10 na d JL=24, the perimeter will be found as follows; the length of one side of the rhombus will be given by Pythagorean theorem, the reason being at the point the diagonals intersect, they form a perpendicular angles; thus c^2=a^2+b^2 hence; c^2=5^2+12^2 c^2=144+25 c^2=169 thus; c=sqrt169 c=13 units; thus the perimeter of the rhombus will be: P=L+L+L+L P=13+13+13+13 P=52 units
