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Flura [38]
2 years ago
5

Base salary is 100 percent, added bonus is 6 percent, total salary is 106 percent.

Mathematics
1 answer:
Lostsunrise [7]2 years ago
6 0

Answer:

22,260

Step-by-step explanation:

You might be interested in
Solve by completing the square x^2-6x-4=0
Vesna [10]

Answer:

x = 3 ± \sqrt{13}

Step-by-step explanation:

x² - 6x - 4 = 0 ( add 4 to both sides )

x² - 6x = 4

To complete the square

add ( half the coefficient of the x- term)² to both sides

x² + 2(- 3)x + 9 = 4 + 9

(x - 3)² = 13 ( take square root of both sides )

x - 3 = ± \sqrt{13} ( add 3 to both sides )

x = 3 ± \sqrt{13}

6 0
2 years ago
Y+7=9/10(x+9) in standard form
sammy [17]
Alright,

-9/10x + y = 1 1/10 
8 0
3 years ago
Unit activity: exponential and logarithmic functions
nirvana33 [79]

We will conclude that:

  • The domain of the exponential function is equal to the range of the logarithmic function.
  • The domain of the logarithmic function is equal to the range of the exponential function.

<h3>Comparing the domains and ranges.</h3>

Let's study the two functions.

The exponential function is given by:

f(x) = A*e^x

You can input any value of x in that function, so the domain is the set of all real numbers. And the value of x can't change the sign of the function, so, for example, if A is positive, the range will be:

y > 0.

For the logarithmic function we have:

g(x) = A*ln(x).

As you may know, only positive values can be used as arguments for the logarithmic function, while we know that:

\lim_{x \to \infty} ln(x) = \infty \\\\ \lim_{x \to0} ln(x) = -\infty

So the range of the logarithmic function is the set of all real numbers.

<h3>So what we can conclude?</h3>
  • The domain of the exponential function is equal to the range of the logarithmic function.
  • The domain of the logarithmic function is equal to the range of the exponential function.

If you want to learn more about domains and ranges, you can read:

brainly.com/question/10197594

3 0
2 years ago
What is the value of the expression (–5) -3 but the -3 is an exponent.
Vanyuwa [196]

Answer:

Answer: -0.008

Step-by-step explanation:

Hope this helped!

6 0
3 years ago
Write an equation of the line that passes through (18, 2) and is parallel to the line 3y−x=−12
rodikova [14]

First isolate the "y" in the equation.

2y - x = -12 Add x on both sides

2y - x + x = -12 + x

2y = -12 + x   Divide 2 on both sides to get "y" by itself

y = \frac{-12 +x}{2}

y = -6 + \frac{x}{2}

Your slope is \frac{1}{2}.

For the equation of the line to be parallel to the given equation, the slopes have to be the same. So the parallel line's slope is also \frac{1}{2}

y = mx + b

y = \frac{1}{2}x + b

To find "b", you plug in the point (18,2) into the equation

y = \frac{1}{2}x + b

2 = \frac{1}{2}(18) + b

2 = 9 + b Subtract 9 on both sides

2 - 9 = 9 - 9 + b

-7 = b


Your equation is:

y =\frac{1}{2}x - 7

8 0
3 years ago
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