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Bas_tet [7]
3 years ago
5

Identify the initial value and rate of change for the graph shown?

Mathematics
1 answer:
valentina_108 [34]3 years ago
3 0

Answer:

The third option, or initial value:2, rate of change:1.

Step-by-step explanation:

The initial value is where the y-intercept is on the y-axis. For this problem it falls on the 2.

Your rate of change is your slope. I like to think of it as rise/run. Your slope in this graph is 1/1. Or just 1.

let me know if your need further explanation!

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The triangles shown have the same perimeter. What is the value of x?
olga nikolaevna [1]

Answer:

18

Step-by-step explanation:

Since you know the perimeters are equal, write your equation.

x+6 + x+6 + x+6 = x + x+6 + 2x-6

combine like terms

3x + 18 = 4x

isolate your x by subtracting 3x from each side

18 = x

check your answer:

3x + 18 = 72

4x = 72

8 0
2 years ago
Given f(x) =7x-4, find the average rate of change over from x=2 to x=4.
yuradex [85]

Answer:

m = (f(4) - f(2)) / (4 - 2)

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6 0
3 years ago
Ms. Knight's two cooking classes are
Radda [10]

Answer:

20

Step-by-step explanation:

In class 1, they used 10 sweet potatoes.

If they need 30, in class 2, they used 20.

5 0
3 years ago
Someone please help me?
Anna35 [415]

Answer:

43

Step-by-step explanation:

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7 0
2 years ago
I need help with this question plzzz <br><br> Geometry
KATRIN_1 [288]

Answer:

  • If the perimeter of a square measures 32 cm, each side measures 32/4= 8 cm, because all sides are equal.
  • The diagonal that passes through the center of the square divides the square into two triangles. The triangles are formed by a <u>hypotenuse </u>(the diagonal, which is k in this case), <u>and two sides,</u> that measure 8 cm each, in this case.
  • Because of Pythagoras' theorem, we know that the <u>lenght of the hypotenuse</u> (in this case the hypotenuse is k) equals the squared root of the sum of the squared sides, which in this case can be expressed as k=\sqrt{8^2+8^2} =\sqrt{64+64}=\sqrt{128}=11.31.
  • Then, k=11.31 cm.

3 0
3 years ago
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