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3 years ago

(3x^(3)-34x^(2)+113x-114)-:(x+3)

Mathematics

1 answer:

Mekhanik [1.2K]3 years ago

7 0

Answer:

honestly i have no clue what the answer is im sorry

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What is the area of a regular hexagon with a side length of 4 m? Enter your answer in the box. Round only your final answer to t

hichkok12 [17]

The area of a hexagon is
A= a^2 (3√3)/2
we replace a with 4
A=41.57

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3 years ago

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Find the unit rate.<br> 12 plates in 4 stacks<br> plates per stack

emmasim [6.3K]

Answer:

Step-by-step explanation:

3 plates per stack

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3 years ago

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Maria and Katy each have a piece of string. When they put the two pieces of string together end to end, the total length is 84in

Serga [27]

Answer: the length of Maria's piece of string is 45 inches.

the length of Katy's piece of string is 39 inches

Step-by-step explanation:

Let x represent the length of Maria's piece of string.

Let y represent the length of Katy's piece of string.

When they put the two pieces of string together end to end, the total length is 84inches. This means that

x + y = 84 - - - - - - - - - - - -1

Maria's string is 6 inches longer than Katy's. This means that

x = y + 6

Substituting x = y + 6 into equation 1, it becomes

y + 6 + y = 84

2y + 6 = 84

2y = 84 - 6 = 78

y = 78/2 = 39

x = y + 6 = 39 + 6

x = 45

8 0

3 years ago

Please help find domain and range

Oxana [17]

<h3>Answer: Choice A</h3>

Domain: x > 4
Range: y > 0

========================================================

Explanation:

We want to avoid having a negative number under the square root. Solving $x-4 \ge 0$ leads to $x \ge 4$

So it appears the domain could involve x = 4 itself; however, if we tried that x value, then we'd get a division by zero error.

So in reality, the domain is x > 4.

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The range of y = sqrt(x) is the set of positive real numbers. So y > 0 is the range for this equation. Shifting left and right does not affect the range, so the range of y = sqrt(x-4) is also y > 0.

We are dividing a positive number (3) over some positive number in the denominator. Overall, the expression $\frac{3}{\sqrt{x-4}}$ is positive because positive/positive = positive.

Therefore, the range of the given equation is y > 0

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The graph is shown below. We have a vertical asymptote at x = 4 and a horizontal asymptote at y = 0. The green curve is fenced in the upper right corner (northeast corner).