Answer: width 2.5 length 4
Step-by-step explanation:
Answer:
Step-by-step explanation:
Answer:
(0, -3)
Step-by-step explanation:
Here we'll rewrite x^2+y^2+6y-72=0 using "completing the square."
Rearranging x^2+y^2+6y-72=0, we get x^2 + y^2 + 6y = 72.
x^2 is already a perfect square. Focus on rewriting y^2 + 6y as the square of a binomial: y^2 + 6y becomes a perfect square if we add 9 and then subtract 9:
x^2 + y^2 + 6y + 9 - 9 = 72:
x^2 + (y + 3)^2 = 81
Comparing this to the standard equation of a circle with center at (h, k) and radius r,
(x - h)^2 + (y - k)^2 = r^2. Then h = 0, k = -3 and r = 9.
The center of the circle is (h, k), or (0, -3).
x = 5 is not an extraneous solution of the equation.
✓(2x + 6) - ✓(x - 1) = 2
✓(2x + 6) = 2 + ✓(x - 1)
Squaring both the sides of equation, we get
(✓(2x + 6))² = (2 + ✓(x - 1))²
2x + 6 = (2)² + (✓(x - 1))² + 2(2)(✓(x - 1))
2x + 6 = 4 + x - 1 + 4(✓(x - 1))
x + 3 = 4✓(x - 1)
Squaring again on both the side of the equation, we get
(x + 3)² = (4✓(x - 1))²
x² + 3² + 2×3×x = 16(x - 1)
x² + 9 + 6x = 16x - 16
x² - 10x + 25 = 0
By applying middle term splitting on equation (1), we get
x² - 5x - 5x + 25 = 0
x(x - 5) -5(x - 5) = 0
(x - 5) (x - 5) = 0
x = 5 and 5.
Check for extraneous solutions by putting value of x in original equation -
✓(2×5 + 6) - ✓(5 - 1) = 2
✓16 - ✓4 = 2
4 - 2 = 2
2 = 2
LHS = RHS
x = 5 is not an extraneous solution of the equation.
Know more about roots of equation -
brainly.com/question/4098861
#SPJ4
3x -1 = -8
x + y = 54
x = 11.50 per novel
y = 42.50 per textbook
