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4 years ago

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Which inequality matches the graph? X, Y graph. X range is negative 10 to 10, and Y range is negative 10 to 10. Dashed line on g

raph has positive slope and runs through negative 10, negative 9 and negative 1, negative 3 and 8, 3. Above line is shaded. −2x + 3y > 7 2x − 3y < 7 −3x + 2y ≥ 7 3x − 2y ≤ 7

1 answer:

LiRa [457]4 years ago

3 0

<h2>Answer:</h2>

The inequality that matches the graph is:

$2x-3y$

<h2>Step-by-step explanation:</h2>

It is given that the line is a dashed line.

This means that the inequality is strict.

Also, the dashed line passes through (-10,-9) and (-1,-3) and (8,3)

Using two point formula we may find the equation of the line.

i.e. any line passing through two points (a,b) and (c,d) is calculated by using the equation:

$y-b=\dfrac{d-b}{c-a}\times (x-a)$

Here (a,b)=(-10,-9) and (c,d)=(-1,-3)

The equation of line is:

$y-(-9)=\dfrac{-3-(-9)}{-1-(-10)}\times (x-(-10))\\\\i.e.\\\\y+9=\dfrac{-3+9}{-1+10}\times (x+10)\\\\i.e.\\\\y+9=\dfrac{6}{9}\times (x+10)\\\\i.e.\\\\y+9=\dfrac{2}{3}\times (x+10)\\\\3(y+9)=2\times (x+10)\\\\3y+27=2x+20\\\\i.e.\\\\2x-3y=27-20\\\\i.e.\\\\2x-3y=7$

Also, the shaded region is above the line.

Hence, the inequality is:

$2x-3y$

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4 years ago

2^-3/2^-5<br><br> A)2^2<br> B)1/2^2<br> C)2^8<br> D)1/2^8

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3 years ago

The matrix below represents a system of equations.

noname [10]

Answer:

The first choice: $a = 1$ , $b = -1$ , and $c = 2$ .

Step-by-step explanation:

$\left[ \begin{array}{ccc|c} 2 & -1 & 1 & 5 \cr 1 & 1 & -1 & -2 \cr 1 & 0 & -3 & -5\end{array} \right]$ .

Add the first row to the second row to obtain:

$\left[ \begin{array}{ccc|c} 2 & -1 & 1 & 5 \cr 2 + 1 & (-1) + 1 & 1 + (-1) & 5 + (-2) \cr 1 & 0 & - 3& -5\end{array} \right]$ .

Simplify that matrix to obtain:

$\left[ \begin{array}{ccc|c} 2 & -1 & 1 & 5 \cr 3 & 0 & 0 & 3\cr 1 & 0 & -3 & -5\end{array} \right]$ .

Divide the second row by $3$ :

$\left[ \begin{array}{ccc|c} 2 & -1 & 1 & 5 \cr 1 & 0 & 0 & 1\cr 1 & 0 & -3& -5\end{array} \right]$ .

Hence, $a = 1$ .

Subtract the current row two from row three:

$\left[ \begin{array}{ccc|c} 2 & -1 & 1 & 5 \cr 1 & 0 & 0 & 1\cr 1 - 1 & 0 & -3 & (-5)- 1 \end{array} \right]$ .

Simplify that matrix to obtain:

$\left[ \begin{array}{ccc|c} 2 & -1 & 1 & 5 \cr 1 & 0 & 0 & 1\cr 0 & 0 & -3 & -6 \end{array} \right]$ .

Invert the signs in the third row and divide it by $3$ to obtain:

$\left[ \begin{array}{ccc|c} 2 & -1 & 1 & 5 \cr 1 & 0 & 0 & 1\cr 0 & 0 & 1 & 2 \end{array} \right]$ .

Hence, $c = 2$ .

Subtract two times the current second row from the first row to obtain:

$\left[ \begin{array}{ccc|c} 2 - (2 \times 1) & -1 & 1 & 5 - 2\times 1\cr 1 & 0 & 0 & 1\cr 0 & 0&1 & 2 \end{array} \right]$ .

That simplifies to

$\left[ \begin{array}{ccc|c} 0 & -1 & 1 & 3\cr 1 & 0 & 0 & 1\cr 0 & 0 & 1& 2\end{array} \right]$ .

Subtract the current third row from the first row to obtain:

$\left[ \begin{array}{ccc|c} 0 & -1 & 1-1 & 3-2\cr 1 & 0 & 0 & 1\cr 0 & 0 & 1& 2\end{array} \right]$ .

That simplifies to

$\left[ \begin{array}{ccc|c} 0 & -1 & 0& 1\cr 1 & 0 & 0 & 1\cr 0 & 0 & 1& 2\end{array} \right]$ .

Invert the signs in the first row to obtain:

$\left[ \begin{array}{ccc|c} 0 & 1 & 0& -1\cr 1& 0 & 0 & 1\cr 0 & 0 & 1& 2\end{array} \right]$ .

Hence, $b = -1$ .

$\left[ \begin{array}{ccc|c}1& 0 & 0 & 1 \cr0 & 1 & 0& -1 \cr 0 & 0 & 1& 2\end{array} \right]$ .

3 0

4 years ago

Help please due today.

yan [13]

Answer:

I think its 2nd one

HOPE IT HELPS, BE SAFE! Brainiest if possible pls! :)

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3 years ago