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Nataly [62]
3 years ago
13

2^-3/2^-5 A)2^2 B)1/2^2 C)2^8 D)1/2^8

Mathematics
1 answer:
CaHeK987 [17]3 years ago
4 0
Here is your answer

A) \huge{2}^{2}

REASON :

CONCEPT USED: \frac{{a}^{m}}{{a}^{n}}

= {a}^{m-n}

So,

\frac{{2}^{-3}}{{2}^{-5}}

= {2}^{-3-(-5)}

= {2}^{-3+5}

= {2}^{2}

HOPE IT IS USEFUL
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What is the value of f(3)?
Anni [7]

Answer:

-12

Step-by-step explanation:

Note that when x < 6, you will use the expression -4x

f(x) = -4x

Plug in 3 for x

f(3) = -4(3)

Simplify. Multiply

f(3) = -4(3)

f(3) = -12

-12 is your answer

5 0
3 years ago
An office building casts a 90 foot shadow. At the same time of day, a 5 foot woman standing near the building casts an 8 foot sh
Elenna [48]
Make a ratio: 
<span>
Make sure shadow is in same location on both fractions (either numerator or denominator) </span>

x/90=5/8 

Cross multiply: 

8x=90x5 
8x=450 
<span>
x=56.25 feet </span>

Therefore, the approximate height of the building to the nearest foot would be 56.25 feet.
<span>
That makes sense, too, because the woman's shadow is taller than she is, but is less than double her height. </span>The building shadow is taller than the building, but it's less than double the height of the building.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.
8 0
3 years ago
Read 2 more answers
Please help me with theses 4 questions
MA_775_DIABLO [31]
1. 864 mm^3
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3 0
3 years ago
I need this done by today someone plzz help me !!!
Pie
(is/of=%/100)
(12/x= 35/100) = 34.29
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8 0
3 years ago
The third term of an arithmetic sequence is 14 and the 9th term is -1. Find the first four terms of the sequence.​
Liula [17]

Answer:

The first four terms of the sequence are :  19, 16.5 , 14 , 11.5

Step-by-step explanation:

In the given sequence:

a(3) =  14, a(9)  = -1

The general term of a sequence in Arithmetic Progression is:

a(n) = a + (n-1)d

a(3) = a + (3 -1) d = a + 2 d

and a(9) = a + (9- 1 ) d = a  + 8 d

⇒   a + 2 d =  14      .........  (1)

and a + 8 d  = -1    ...........  (2)

Now, solving the given system of equation, we get:

From (1), a  = 14 - 2 d

Put in (2), we get:

a + 8 d  = -1                ⇒   14 - 2 d + 8d = -1

⇒  14 +   6d   = -1  

or,  6d = -1 -14 = -15

⇒  d = -15/6 = -2.5

or, d  = -2.5

Then a  = 14 - 2 d = 14 - 2(-2.5)  =14 + 5  = 19, or a  = 19

Now, first four terms of the sequence is:

a = 19

a(2) = a + 4 = 19 - 2.5 = 16.5

a(3) = a + 2d = 19 + 2(-2.5) = 19 - 5 = 14

a(4) = a  + 3d = 19 + 3(-2.5)  = 19  - 7.5  = 11.5

Hence, the first four terms of the sequence are :  19, 16.5 , 14 , 11.5

4 0
3 years ago
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