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Rom4ik [11]
3 years ago
8

Of five letters (a, b, c, d, and e), two letters are to be selected at random. how many possible selections are there

Mathematics
1 answer:
Margaret [11]3 years ago
5 0
You can use C(5,2) which is 5*4/2 which makes 10!
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Solve 5n+7=7(n+l)-2n <br>​
notsponge [240]

Answer: The answer is 1 =n and my work is in the bottom and hope this help :)

Step-by-step explanation:

5n+7=7(n+l)-2n distributive property

5n+7=7n+7-2n  Combines Like Term

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4 0
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