Answer:
The probability that the mean from that sample will be between 183 and 186 is 0.0994 = 9.94%.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean
and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
A population has a mean of 180 and a standard deviation of 24.
This means that ![\mu = 180, \sigma = 24](https://tex.z-dn.net/?f=%5Cmu%20%3D%20180%2C%20%5Csigma%20%3D%2024)
A sample of 100 observations will be taken.
This means that ![n = 100, s = \frac{24}{\sqrt{100}} = 2.4](https://tex.z-dn.net/?f=n%20%3D%20100%2C%20s%20%3D%20%5Cfrac%7B24%7D%7B%5Csqrt%7B100%7D%7D%20%3D%202.4)
The probability that the mean from that sample will be between 183 and 186 is:
This is the pvalue of Z when X = 186 subtracted by the pvalue of Z when X = 183. So
X = 186
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
By the Central Limit Theorem
![Z = \frac{X - \mu}{s}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7Bs%7D)
![Z = \frac{186 - 180}{2.4}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B186%20-%20180%7D%7B2.4%7D)
![Z = 2.5](https://tex.z-dn.net/?f=Z%20%3D%202.5)
has a pvalue of 0.9938
X = 183
![Z = \frac{X - \mu}{s}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7Bs%7D)
![Z = \frac{183 - 180}{2.4}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B183%20-%20180%7D%7B2.4%7D)
![Z = 1.25](https://tex.z-dn.net/?f=Z%20%3D%201.25)
has a pvalue of 0.8944
0.9938 - 0.8944 = 0.0994
The probability that the mean from that sample will be between 183 and 186 is 0.0994 = 9.94%.