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Sonja [21]
3 years ago
5

Two swimmers start out from opposite ends of a swimming pool(red side and blue side). They cross each other for the first time a

t line PQ, which is 21 yards from the red side and 29 yards from the blue side. They reach the opposite ends, turn around and cross again at line RS. Assuming that they both travel at constant speeds, how far is line RS from the blue side? The line RS is to the right of line PQ, which is 21 feet from the red side.
Mathematics
1 answer:
daser333 [38]3 years ago
7 0

Answer:

13 yds

Step-by-step explanation:

the blue side starter (B) swims 29yd in the time it takes the red side starter (R) to swim 21yd

their combined distance, when they meet, is 50yd (length of pool)

 

they pass each other and continue to the ends of the pool (combined distance, 100yd)

they swim towards each other again, and pass a second time (combined distance, 150yd)

at this point, R has swum 63yd (3*21) -- one length plus 13yd

so RS is 13yd from the blue end

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X-3=2x-3-x<br> Please solve with answer and how you got the answer
Fofino [41]

Answer:

3x-3

Step-by-step explanation:

You have to combine like terms. <em>x</em> and 2<em>x</em> have the same variable, so this equals 3x, and then you subtract 3 so:

x-3=2x-3-x

    =3x-3

3 0
3 years ago
The distance around the middle of a sphere (the circumference) equals 37.699 in. what is the surface area of the sphere?
podryga [215]

To solve this problem you must apply the proccedure shown below:

1. Clear the radius from the formula for the circumference of a circle and substitute values, as following:

C=2\pi r\\ r=C/2\pi \\ r=37.699in/2\pi \\ r=5.99in

2. Substitute the radius calculated into the formula for calculate the surface area of the sphere:

SA=4\pi r^{2} \\ SA=4\pi(5.99in^{2})\\ SA=450.88in^{2}

The answer is: 450.88in^{2}

5 0
3 years ago
The percentage of body fat of a random sample of 36 men aged 20 to 29 found a sample mean of 14.42. Find a 95% confidence interv
Rina8888 [55]

Answer:

14.42-1.96\frac{6.95}{\sqrt{36}}=12.150    

14.42+ 1.96\frac{6.95}{\sqrt{36}}=16.690    

So on this case the 95% confidence interval would be given by (12.150;16.690)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=14.42 represent the sample mean

\mu population mean (variable of interest)

\sigma=6.95 represent the population standard deviation

n=36 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

14.42-1.96\frac{6.95}{\sqrt{36}}=12.150    

14.42+ 1.96\frac{6.95}{\sqrt{36}}=16.690    

So on this case the 95% confidence interval would be given by (12.150;16.690)    

5 0
4 years ago
Ashley multiplied 9 x 0.942 and got 84.78. How can you use estimation to show that Ashley's answer is wrong? Use whole numbers t
exis [7]

Answer:

Calculate the percent value:

0.942 =

0.942 × 100/100 =

(0.942 × 100)/100 =

94.2/100 =

94.2%;

In other words:

1) Multiply that number by 100.

2) Add the percent sign % to it.

Answer:

0.942 = 94.2%

Step-by-step explanation:

7 0
3 years ago
Which of the pairs of events below is mutually exclusive?
Nady [450]

Answer:

Drawing an ace of spades and then drawing another ace of spades without replacement from a standard deck of cards.

Step-by-step explanation:

Given four pair of events:

1. Drawing an ace of spades and then drawing another ace of spades without replacement from a standard deck of cards

2. Drawing a 2 and drawing a 4 with replacement from a standard deck of cards

3. Drawing a heart and then drawing a spade without replacement from a standard deck of cards

4. Drawing a jack and then drawing a 7 without replacement from a standard deck of cards

To find:

Which of the pairs is mutually exclusive?

Solution:

First of all, let us have a look at the definition of mutually exclusive events.

Mutually exclusive events do not have any case in common.

In other words, two events are known as mutually exclusive when both the events can not occur at the same time.

Now, let us have a look at the given options one by one:

1. Drawing an ace of spades and then drawing another ace of spades without replacement from a standard deck of cards.

We know that there is only one ace of spades in a standard deck.

Therefore, the two events can not occur one after the other, so these are mutually exclusive events.

2. Drawing a 2 and drawing a 4 with replacement from a standard deck of cards.

The two events can occur one after the other, so these are not mutually exclusive.

3. Drawing a heart and then drawing a spade without replacement from a standard deck of cards.

Separate cards are drawn one after the other, so not mutually exclusive.

4. Drawing a jack and then drawing a 7 without replacement from a standard deck of cards.

Separate cards are drawn one after the other, so not mutually exclusive.

3 0
3 years ago
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