The top row of matrix A (1, 2, 1) is multiplied with the first column of matrix B (1,0,-1) and the result is 1x1 + 2x0 + 1x -1 = 0 this is row 1 column 1 of the resultant matrix
The top row of matrix A (1,2,1) is multiplied with the second column of matrix B (-1, -1, 1) and the result is 1 x-1 + 2 x -1 + 1 x 1 = -2 , this is row 1 column 2 of the resultant matrix
Repeat with the second row of matrix A (-1,-1.-2) x (1,0,-1) = 1 this is row 2 column 1 of the resultant matrix, multiply the second row of A (-1,-1,-2) x (-1,-1,1) = 0, this is row 2 column 2 of the resultant
Repeat with the third row of matrix A( -1,1,-2) x (1,0, -1) = 1, this is row 3 column 1 of the resultant
the third row of A (-1,1,-2) x( -1,-1,1) = -2, this is row 3 column 2 of the resultant matrix
Matrix AB ( 0,-2/1,0/1,-2)
Recall that for a home visit, the technician charges $50 regardless on the time spent in the repair.
So, to find out the rate, we should calculate the part that depends on the spent time, and the add 50. So for example, we know that the technician spents 1 hour. So, we multiply 1 times 25 and then add 50. So, 25*1 + 50 = 75, which is the rate for a 1-hour repair.
So, in general, if we know that the number of hours is x, we multiply x times 25 and then add 50. Then a table would like this:
x 25*x 25*x +50
1 25 75
2 50 100
3 75 125
4 100 150
Note that as the time increases by one hour, the fare increases by 25. This is an example of a direct variation, since as the independent variable increases (t
Answer:
d. 1 grid equals 1 hour
Step-by-step explanation:
When plotting research data, X-axis(or horizontal axis) usually used for independent variable and Y-axis is used for the dependent variable. In this case, Heather wants to know how much earning on different numbers of hours. The dependent variable is the earning and the independent variable is the hours, so you put hours on the horizontal axis.
You want to make a 10x10 grid of data and the hours ranged between 1-10. If you plot them equally, approximate scale will be: (10h-1h)/(10)= 0.9h/grid
The closest option is 1 hour per grid. It will provide the best visualization since it won't stretch or minimize the data too much.
Answer:
60
Step-by-step explanation:
calculated it with scientific calculator
359 is the correct answer for the English one I think
