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Blababa [14]
3 years ago
10

Can someone help me please​

Mathematics
2 answers:
Anettt [7]3 years ago
7 0

Answer:

9

Step-by-step explanation:

can I have brainliest :)

kakasveta [241]3 years ago
3 0

Answer:

12.32

Step-by-step explanation:

So by using y1 +y2/x1+x2 we can find the ratio.

the y1  will be 4 and  y2 will be 13.

the x1 will be 5 and x2 will be 6

this is equivilent to  17/11 (4+13/5+6)

17/11 =1.54545454... we can simplify to 1.54

8*1.54=12.32

this might be wrong I  haven't   done this math in years

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The time between arrivals of customers at the drive-up window of a bank follows an exponential probability distribution with a m
castortr0y [4]

Answer:

a) 50.34% probability that the arrival time between customers will be 7 minutes or less.

b) 24.42% probability that the arrival time between customers will be between 3 and 7 minutes

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

Mean of 10 minutes:

This means that m = 10, \mu = \frac{1}{10} = 0.1

A. What is the probability that the arrival time between customers will be 7 minutes or less?

P(X \leq x) = 1 - e^{-\mu x}

P(X \leq 7) = 1 - e^{-0.1*7} = 0.5034

50.34% probability that the arrival time between customers will be 7 minutes or less.

B. What is the probability that the arrival time between customers will be between 3 and 7 minutes?

P(3 \leq X \leq 7) = P(X \leq 7) - P(X \leq 3)

P(X \leq x) = 1 - e^{-\mu x}

P(X \leq 7) = 1 - e^{-0.1*7} = 0.5034

P(X \leq 3) = 1 - e^{-0.1*3} = 0.2592

P(3 \leq X \leq 7) = P(X \leq 7) - P(X \leq 3) = 0.5034 - 0.2592 = 0.2442

24.42% probability that the arrival time between customers will be between 3 and 7 minutes

3 0
3 years ago
The 1 in the hundred thousands place is the value of the middle 1 911,147,837
andrew-mc [135]
<span>The 1 in the hundred thousands place is the value of the middle of 1 and 4.</span>
4 0
3 years ago
GIVING BRAINIEST IF CORRECT!!<br><br> Factor x^4 - 16 completely
ioda

Answer:

(x^2 + 4)(x + 2)(x - 2)

Step-by-step explanation:

Hello!

We can use the difference of square method.

<h2>Difference Of Squares (DOS)</h2>

The formula for the DOS is (a + b)(a - b) = a^2 - b^2

It is a simple way to factor polynomials.

The criteria:

  • Has to begin and end with a perfect square
  • The operation has to be subtraction

<h3>Factor:</h3>
  • x^4 - 16

Begins with a perfect square (x² * x²) and ends with a perfect square (4 * 4)

  • (x^2 + 4)(x^2 - 4)

Warning! Watch out, there may be another DOS!

x^2 - 4 is another DOS

  • (x^2 + 4)(x + 2)(x - 2)

The x² + 4 is not a DOS because the operation is addition.

The final factored form is (x^2 + 4)(x + 2)(x - 2)

8 0
2 years ago
Sara takes 1/6 of an hour to vacuum his moms car it takes 4 times that long to wash the car then it takes you to wax the car twi
Nataly [62]
<h2>Answer:</h2><h2>2 hours & 10 minutes </h2><h2>Step-by-step explanation:</h2><h2>1/6 of an hour is 10 minutes. She vacuumed for 10 minutes. It took 4 times as long to wash the car so 10 * 4 = 40. She washed the car for 40 minutes. It took her twice as long to wax the car as it did for her to wash it so 40 * 2 = 80. She waxed the car for 80 minutes. 10 + 40 + 80 = 130 minutes or 2 hours and 10 minutes. </h2>
3 0
3 years ago
Which of the following equations is of the parabola whose vertex is at (2, 3), axis of symmetry parallel to the y-axis and p = 4
lora16 [44]

Answer:

option A.) y-3 = 1/16 (x-2)^2

Step-by-step explanation:

we know that

If the axis of symmetry is parallel to the y-axis, then we have a vertical parabola

The equation of a vertical parabola is equal to

4p(y-k)=(x-h)^{2}

where

(h,k) is the vertex

In this problem we have

(h,k)=(2,3)

p=4

substitute

4(4)(y-3)=4(4)(x-2)^{2}

16(y-3)=(x-2)^{2}

(y-3)=(1/16)(x-2)^{2}

8 0
3 years ago
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