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Luden [163]
3 years ago
15

A restaurant is giving away 1 of 5 different toys with its

Mathematics
1 answer:
In-s [12.5K]3 years ago
3 0
All of the toys would be given out theoretically and 1 extra of the 5 toys would be given out in total.
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I need help with this question please<br> Help!!
ololo11 [35]

Answer:

step-by-step explanation:

15 I think Or it could be 12/3

8 0
3 years ago
I need help on this....7th grade math!!​
Basile [38]

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The answer is no.

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All you have to do is plot the points and see if they match up.

4 0
2 years ago
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shutvik [7]

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the solution for x is -5.

Step-by-step explanation:

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7 0
3 years ago
Draw lines to connect each repeating decimal on the left with an equivalent fraction on the right . Hurry !!
mina [271]

Answer:  0.17 (bar over 17) = 17/99

               0.351 (bar over 351) = 351/99

               0.17 (bar over 7) = 16/90 = 8/45

               0.351 (bar over 51) = 348/990 = 58/165

               0.351 (bar over 1) = 316/900 = 79/225

<u>Step-by-step explanation:</u>

A bar over a number means it is a repeating decimal.  Instead of dividing the value by 10, 100, 1000, etc, you need to divide by 9, 90, 900, etc.

0.17 (bar over 17) = 17/99 --> <em>two digits under the bar so denominator has two 9s</em>

0.351 (bar over 351) = 351/999  ---> <em>three digits under the bar so denominator has three 9s</em>

0.17 (bar over 7) = 1/10 + 7/90  = 9/90 + 7/90  = 16/90  ---> <em>one digit under the bar so denominator has one 9 & one digit not under the bar so it has one zero in the denominator</em>

0.351 (bar over 51) = 3/10 + 51/990 = 297/990 + 51/990 = 348/990  ---> <em>two digits under the bar so denominator has two 9s & one digit not under the bar so it has one zero in the denominator</em>

0.351 (bar over  1) = 35/100 + 1/900 = 315/900 + 1/900 = 316/900   ---> <em>one digit under the bar so denominator has one 9 & two digits not under the bar so it has two zeros in the denominator</em>

5 0
4 years ago
What is the product? 6(x*2-1)(6x-1/6(x+1))
Yanka [14]
6(x^2-1)(6x-1/6(x+1))

On factoring (x^2-1)=(x+1)(x-1)

= 6(x-1)(x+1)(6x-1/6(x+1))
Cancelling (x+1) from numerator and denominator we get,

= 6(x-1)(6x-1)/6

Cancelling 6 we get,
= (x-1)(6x-1)
4 0
3 years ago
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