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AysviL [449]
3 years ago
10

The owner of a convenience store keeps track of how many customer buy lunch food during the "noon rush" each day for four days a

nd calculates that the mean number of customers for those four days is 52. How many customers must come in on the fifth day to make the five-day mean 54?
a) 54
b) 60
c) 62
Mathematics
1 answer:
alexdok [17]3 years ago
4 0

Answer:

c) 62.

Step-by-step explanation:

Let x represent number of customers came in on the fifth day.

We have been given that the mean number of customers for those four days is 52. So total number of customers on 4 days would be 4 times 52 that is 208 customers.

We know that mean of a data set is equal to sum of all data points divided by number of data points.

Total number of customers on 5 days would be 208+x and total number of days is 5.

Since we need a mean of 54, so we can set mean of 5 days equal to 54 as:

\frac{208+x}{5}=54

Multiply both sides by 5:

\frac{208+x}{5}*5=54*5

208+x=270

208-208+x=270-208

x=62

Therefore, 62 customers must come in on the fifth day to make the five-day mean 54 and option 'c' is the correct choice.

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

In order to solve for x, we must isolate x on one side of the equation.

x+3x+5=21

First, combine like terms. x and 3x are both terms with variables, and can be combined.

(x+3x) + 5=21

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5 is being added to 4x. The inverse of addition is subtraction. Subtract 5 from both sides of the equation.

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x is being multiplied by 4. The inverse of multiplication is division. Divide both sides by 4.

4x/4=16/4

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Let's check our solution. Plug 4 in for x and solve.

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This solution checks out, so we know our answer is correct.

x is equal to 4, x=4.

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