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Tanzania [10]
2 years ago
10

Need help ASAP please

Mathematics
1 answer:
Misha Larkins [42]2 years ago
6 0

Answer: try the second one

Step-by-step explanation:

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Segment BC is a midsegment of triangle TUV. What is the length of segment VC? (A)a (B)2b (C)b (D)c
Ganezh [65]
It would be twice whatever the midsegment equals.
7 0
3 years ago
If f(x) =7 +4x and g(x) =1/2 what is the value of (f/g)
saw5 [17]

Answer:

10.8

Step-by-step explanation:

To find (f/g)(5), find f(5) and (g5) then divide the values.

f(5) = 7 + 4(5) = 27

g(5) = 1/2 (5) = 2.5

27/2.5 = 10.8

6 0
3 years ago
Which value of n makes the equation true?<br><br> 2/3n = -12
vivado [14]

Answer:

-1/18

Step-by-step explanation:

Let's multiply left and right by 3n:

2 = -12 * 3n =>

-36n = 2

now divide by -36:

n = 2/-36 = -1/18

5 0
2 years ago
Read 2 more answers
Assume that the helium porosity (in percentage) of coal samples taken from any particular seam is normally distributed with true
IgorLugansk [536]

Answer:

(a) 95% confidence interval for the true average porosity of a certain seam is [4.52 , 5.18].

(b) 98% confidence interval for the true average porosity of a another seam is [4.12 , 4.99].

Step-by-step explanation:

We are given that the helium porosity (in percentage) of coal samples taken from any particular seam is normally distributed with true standard deviation 0.75.

(a) Also, the average porosity for 20 specimens from the seam was 4.85.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

                      P.Q. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample average porosity = 4.85

            \sigma = population standard deviation = 0.75

            n = sample of specimens = 20

            \mu = true average porosity

<em>Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.</em>

<u>So, 95% confidence interval for the true mean, </u>\mu<u> is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                                     of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.96) = 0.95

P( -1.96 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

P( \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ]

                                            = [ 4.85-1.96 \times {\frac{0.75}{\sqrt{20} } } , 4.85+1.96 \times {\frac{0.75}{\sqrt{20} } } ]

                                            = [4.52 , 5.18]

Therefore, 95% confidence interval for the true average porosity of a certain seam is [4.52 , 5.18].

(b) Now, there is another seam based on 16 specimens with a sample average porosity of 4.56.

The pivotal quantity for 98% confidence interval for the population mean is given by;

                      P.Q. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample average porosity = 4.56

            \sigma = population standard deviation = 0.75

            n = sample of specimens = 16

            \mu = true average porosity

<em>Here for constructing 98% confidence interval we have used One-sample z test statistics as we know about population standard deviation.</em>

<u>So, 98% confidence interval for the true mean, </u>\mu<u> is ;</u>

P(-2.3263 < N(0,1) < 2.3263) = 0.98  {As the critical value of z at 1% level

                                                   of significance are -2.3263 & 2.3263}  

P(-2.3263 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 2.3263) = 0.98

P( -2.3263 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} <  2.3263 ) = 0.98

P( \bar X-2.3263 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+2.3263 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.98

<u>98% confidence interval for</u> \mu = [ \bar X-2.3263 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+2.3263 \times {\frac{\sigma}{\sqrt{n} } } ]

                                            = [ 4.56-2.3263 \times {\frac{0.75}{\sqrt{16} } } , 4.56+2.3263 \times {\frac{0.75}{\sqrt{16} } } ]

                                            = [4.12 , 4.99]

Therefore, 98% confidence interval for the true average porosity of a another seam is [4.12 , 4.99].

7 0
3 years ago
WILL GIVE A BRAINLEST
Gnoma [55]

Answer: "No, the triangles are not necessarily congruent." is the correct statement .


Step-by-step explanation:

In ΔCDE, m∠C = 30° and m∠E = 50°

Therefore by angle sum property of triangles

m∠C+m∠D+m∠E=180°

⇒m∠D=180°-m∠E-m∠C=180°-30°-50°=100°

⇒m∠D=100°

In ΔFGH, m∠G = 100° and m∠H = 50°

Similarly m∠F +∠G+m∠H=180°

⇒m∠F=180°-∠G-m∠H=180°-100°-50=30°

⇒m∠F=30°

Now ΔCDE and ΔFGH

m∠C=m∠F=30°,m∠D=m∠G=100°,m∠E=m∠H=50°

by AAA similarity criteria  ΔCDE ≈ ΔFGH but can't say congruent.

Congruent triangles are the pair of triangles in which corresponding sides and angles are equal . A congruent triangle is a similar triangle but a similar triangle may not be a congruent triangle.


8 0
3 years ago
Read 2 more answers
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