Given a polynomial
and a point
, we have that

We know that our cubic function is zero at -4, 0 and 5, which means that our polynomial is a multiple of

Since this is already a cubic polynomial (it's the product of 3 polynomials with degree one), we can only adjust a multiplicative factor: our function must be

To fix the correct value for a, we impose
:

And so we must impose

So, the function we're looking for is

Answer:
87 3/4
Step-by-step explanation:
in order to get your answer u will have to subtract
the last one D)4.5298 l check in calculator it did not come correct but I say the last one