<span>30 is 40% of 75 so it should be 45
</span>
Answer:
Step-by-step explanation:
Let 
![m=(y^3)^{\frac{1}{2}}\\\\m=y^{3\times \frac{1}{2}}\ \ \ \ \ \ \ \ \ [as\ (x^a)^b=x^{ab}]\\\\m=y^{\frac{3}{2}](https://tex.z-dn.net/?f=m%3D%28y%5E3%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5C%5C%5C%5Cm%3Dy%5E%7B3%5Ctimes%20%5Cfrac%7B1%7D%7B2%7D%7D%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5Bas%5C%20%28x%5Ea%29%5Eb%3Dx%5E%7Bab%7D%5D%5C%5C%5C%5Cm%3Dy%5E%7B%5Cfrac%7B3%7D%7B2%7D)
Answer:
what whats the question so I can answer
Thus L.H.S = R.H.S that is 2/√3cosx + sinx = sec(Π/6-x) is proved
We have to prove that
2/√3cosx + sinx = sec(Π/6-x)
To prove this we will solve the right-hand side of the equation which is
R.H.S = sec(Π/6-x)
= 1/cos(Π/6-x)
[As secƟ = 1/cosƟ)
= 1/[cos Π/6cosx + sin Π/6sinx]
[As cos (X-Y) = cosXcosY + sinXsinY , which is a trigonometry identity where X = Π/6 and Y = x]
= 1/[√3/2cosx + 1/2sinx]
= 1/(√3cosx + sinx]/2
= 2/√3cosx + sinx
R.H.S = L.H.S
Hence 2/√3cosx + sinx = sec(Π/6-x) is proved
Learn more about trigonometry here : brainly.com/question/7331447
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