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option B is the answer of this question
I’m not sure i’m pretty sure it’s 28
The solutions of the equations of the situation can be:
z = 1 , y = 5, x = 4
z= 2 , y = 3, x = 5
z=3 , y = 1, x = 6
z = 0 , y = 7, x =3
The question can be expressed as a equation
6 x + 8 y + 10 z = 84
also, x + y + z = 10
⇒ x = 10- y - z
Putting it in first equation,
6(10 - y - z ) +8y + 10z = 84
⇒ 60 +2y + 4z = 84
⇒2(y + 2z ) = 14
⇒ y + 2z = 7
Now putting
z = 1 , we get y = 5,
z= 2 , y = 3
z=3 , y = 1
z = 0 , y = 7
So, only 4 possible solutions.
Therefore, there can only be 4 possible solutions for the equations.
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Answer:
7.2
Step-by-step explanation:
First differences:
0.8-0.2, 1.8-0.8, 3.2-1.8, 5.0-3.2
0.6, 1.0, 1.4, 1.8
Second differences:
1.0-0.6, 1.4-1.0, 1.8-1.4
0.4, 0.4, 0.4
For the next term, add 0.4 to the last term from the first differences, and add the sum to the last term of the quadratic sequence:
0.4+1.8=2.2
2.2+5.0=7.2
∴ The next term in the sequence is 7.2
