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4 years ago

Write comparison using numbers below 34,930 34,390 34,093

Mathematics

1 answer:

Komok [63]4 years ago

5 0

They all have 34,000

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What is the answer to 4(y-1)-1=2(2y-3)

Ostrovityanka [42]

4(y - 1) - 1 = 2(2y - 3)
4(y) - 4(1) - 1 = 2(2y) - 2(3)
4y - 4 - 1 = 4y - 6
4y - 5 = 4y - 6
- 4y - 4y
-5 ≠ -6

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4 years ago

A chair is on sale at a price of £20.80. This is a 20% reduction of the normal price what was the price of the chair before the

Vladimir [108]

Answer:

Explanation is in photo

Step-by-step explanation:

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3 years ago

Graph a line with a slope of -3 that contains the point (4,-2).

True [87]

Answer:

the line is going to be negative

start the line on (4, -2) so you know the line will contact the point

make sure the slope is -3

i dont know how else to help

Step-by-step explanation:

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3 years ago

The following graph shows the solution to which system of inequalities?

ANTONII [103]

Looking at the purple area, we see that 1≤y≤3. So we can immediately reject answers (d), (a).

Since the purple area is to the right of and above the sloping line, we choose answer (c).

The correct answer to the whole problem is (c).

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3 years ago

Read 2 more answers

Find all relative extrema of the function. Use the Second Derivative Test where applicable. (If an answer does not exist, enter

Lapatulllka [165]

Answer:

Relative minimum: $\left(-\frac{5}{2}, -\frac{33}{4}\right)$ , Relative maximum: $DNE$

Step-by-step explanation:

First, we obtain the First and Second Derivatives of the polynomic function:

First Derivative

$f'(x) = 2\cdot x + 5$ (1)

Second Derivative

$f''(x) = 2$ (2)

Now, we proceed with the First Derivative Test on (1):

$2\cdot x + 5 = 0$

$x = -\frac{5}{2}$

The critical point is $-\frac{5}{2}$ .

As the second derivative is a constant function, we know that critical point leads to a minimum by Second Derivative Test, since $f\left(-\frac{5}{2}\right) > 0$ .

Lastly, we find the remaining component associated with the critical point by direct evaluation of the function:

$f\left(-\frac{5}{2} \right) = \left(-\frac{5}{2} \right)^{2} + 5\cdot \left(-\frac{5}{2} \right) - 2$

$f\left(-\frac{5}{2} \right) = -\frac{33}{4}$

There are relative maxima.

6 0

3 years ago