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AleksandrR [38]

2 years ago

8

A hole is being dug into the ground at a rate of 5.3 feet per minute. Write an integer to describe the depth of the hole after 1

5 minutes.

1 answer:

inna [77]2 years ago

8 0

Answer:

79.5 feet

Step-by-step explanation:

5.3 per minute can also be written as the ratio 5.3:1. so if we have x:15, we can see that we've multiplied the right side by 15 so we have to do the same to the other side. 15 times 5.3 is 79.5. so thats your answer.

i hope this helps :))

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Pachacha [2.7K]

Answer:

F is not a function

Step-by-step explanation:

There is more than 1 corresponding y coordinate per x coordinate

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2 years ago

Math question please help <br> If you get this right I will mark you as a brainliest

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2 years ago

What is the constant rate of change in the equation?<br> Y=5x+10

mezya [45]

Answer:

$m =5$

Step-by-step explanation:

================================================

The "<em>constant rate of change</em>" is also known as the slope (in straight line equations).

The equation is in <em>slope-intercept form</em>.

================================================

<em>Slope-Intercept Form is: </em>

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<em>Hope this helps.</em>

6 0

2 years ago

Read 2 more answers

Let a, b, c and x elements in the group G. In each of the following solve for x in terms of a, b, and c.

alina1380 [7]

Answer:

The answer is $x=a^{-1}cb^{-1}$ .

Step-by-step explanation:

First, it is important to recall that the group law is not commutative in general, so we cannot assume it here. In order to solve the exercise we need to remember the axioms of group, specially the existence of the inverse element, i.e., for each element $g\in G$ there exist another element, denoted by $g^{-1}$ such that $gg^{-1}=e$ , where $e$ stands for the identity element of G.

So, given the equality $axb=c$ we make a left multiplication by $a^{-1}$ and we obtain:

$a^{-1}axb =a^{-1}c.$

But, $a^{-1}axb = exb = xb$ . Hence, $xb = a^{-1}c$ .

Now, in the equality $xb = a^{-1}c$ we make a right multiplication by $b^{-1}$ , and we obtain

$xbb^{-1} = a^{-1}cb^{-1}$ .

Recall that $bb^{-1}=e$ and $xe=x$ . Therefore,

$x=a^{-1}cb^{-1}$ .

6 0

2 years ago

A submarine travels 6.6 km due West from its base and then turns and travels due South for 3.9

geniusboy [140]

Answer:

$7.7$ km

Step-by-step explanation:

The submarine's path from its base forms a right triangle when its final position is "connected" to the base. We know that the right triangle has legs of $6.6$ km and $3.9$ km, and we need to find the length of its hypotenuse. To do so, we can use the Pythagorean Theorem, which states that in a right triangle, $a^{2}+b^{2} =c^{2}$ , where $a$ and $b$ are the lengths of the triangle's legs and $c$ is the length of the triangle's hypotenuse. In this case, we know what $a$ and $b$ are, and we need to solve for c, so after substituting the given values of $a$ and $b$ into $a^{2}+b^{2} =c^{2}$ to solve for c, we get:

$a^{2}+b^{2} =c^{2}$

$6.6^{2} +3.9^{2} =c^{2}$ (Substitute $a=6.6$ and $b=3.9$ into the equation)

$43.56+15.21=c^{2}$ (Evaluate the squares on the LHS)

$58.77=c^{2}$ (Simplify the LHS)

$c^{2}=58.77$ (Symmetric Property of Equality)

$\sqrt{c^{2} } =\sqrt{58.77}$ (Take the square root of both sides of the equation)

$c=7.7,c=-7.7$ (Simplify)

$c=-7.7$ is an extraneous solution because you can't have negative distance, if that makes sense, so therefore, the submarine is approximately $7.7$ km away from its base. Hope this helps!

7 0

2 years ago