Question

URGENT PLEASE HELP 98 POINTS Find the direction angle of vector v to the nearest tenth of a degree.

Answer 1

Answer:

The direction angle of vector v is equal to  9.5\°

Step-by-step explanation:

Let

A(-5,0),B(7,2)

The vector v is given by

v=B-A

v=(7, 2) - (-5, 0)

v=((7 - (- 5)), (2-0))

v=(12, 2)

Remember that

The direction angle of the vector is equal to

tan (\theta) =\frac{y}{x}

substitute the values

tan (\theta) =\frac{2}{12}

\theta=arctan(\frac{2}{12})=9.5\°

Step-by-step explanation:

put that in a computer calc and  it shoud give u the awnser

Answer 2

Answer:

 The direction angle of vector v is equal to  $9.5\°$

Step-by-step explanation:

Let

$A(-5,0),B(7,2)$

The vector v is given by

$v=B-A$

$v=(7, 2) - (-5, 0)$

$v=((7 - (- 5)), (2-0))$

$v=(12, 2)$

 Remember that

The direction angle of the vector is equal to

 $tan (\theta) =\frac{y}{x}$

substitute the values

 $tan (\theta) =\frac{2}{12}$

 $\theta=arctan(\frac{2}{12})=9.5\°$