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My name is Ann [436]
4 years ago
8

Jana is making greeting cards that are 4 inches long and 3.5 inches wide to sell at a craft fair. She decorates each card by put

ting a strip of red ribbon along the border all the way around the card.
Mathematics
1 answer:
Sveta_85 [38]4 years ago
8 0

Answer:

15 inches of ribbon is needed.

Step-by-step explanation:

To find how much ribbon is needed to go around the edge of the card, find the perimeter. The perimeter is the length around the card.

Perimeter is found by P = 2l + 2w where w=3.5 and l=4.

P = 2(4) + 2(3.5)

P = 8 + 7

P = 15 inches

15 inches of ribbon is needed.

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Solve the following equation for A. Be sure to take into account whether a letter is
Lubov Fominskaja [6]
Isolate the variable by dividing each side by factors that don't contain the variable.

a = 4 √69m^3/m

That 3 is on top of the m
4 0
4 years ago
35 of the apartments have a balcony and 55 of them don't. An apartment is randomly selected as part of a survey. What is the pro
kobusy [5.1K]

Answer:

39%

Step-by-step explanation:

It is given that 35 apartments have balconies in them.

While 55 apartments do not have balconies in them.

Total number of balconies is the sum of the apartments. i.e. 35 + 55

                                                                                             = 90 apartments

Therefore for the survey when an apartment is randomly selected, the percentage of the probability of the apartment to have a balcony can be found out by dividing 35 by 90 and then multiply by 100.

i.e.

$=\frac{35}{90}$

= 0.38888888

Multiplying by 100, we get

= 0.388888 x 100

= 38.8888 %

= 39 %

3 0
3 years ago
Which fraction is equal to 1hole and 2/5?<br> a.3/5<br> b.75<br> c.57<br> d.73
zimovet [89]

Answer:

7/5

Step-by-step explanation:

This would be equal to 5/5 (the 1 hole) and 2/5

3 0
3 years ago
Read 2 more answers
In a shipment of 20 packages, 7 packages are damaged. The packages are randomly inspected, one at a time, without replacement, u
horsena [70]

Answer:

      \large\boxed{\large\boxed{0.119}}

Explanation:

You need to find the probability that exactly three of the first 11 inspected packages are damaged and the fourth is damaged too.

<u>1. Start with the first 11 inspected packages:</u>

a) The number of combinations in which 11 packages can be taken from the 20 available packages is given by the combinatory formula:

     C(m,n)=\dfrac{m!}{m!(m-n)!}

      C(20,11)=\dfrac{20!}{11!\cdot(20-11)!}

b) The number of combinations in which 3 damaged packages can be chossen from 7 damaged packages is:

      C(7,3)=\dfrac{7!}{3!\cdot(7-3)!}

c) The number of cominations in which 8 good packages can be choosen from 13 good pacakes is:

      C(13,8)=\dfrac{13!}{8!\cdot(13-8)!}

d) The number of cominations in which 3 damaged packages and 8 good packages are chosen in the first 11 selections is:

         C(7,3)\times C(13,8)

e) The probability is the number of favorable outcomes divided by the number of possible outcomes, then that is:

        \dfrac{C(7,3)\times C(13,8)}{C(20,11)}

Subsituting:

             \dfrac{\dfrac{7!}{3!\cdot(7-3)!}\times \dfrac{13!}{8!\cdot(13-8)!}}{\dfrac{20!}{11!\cdot(20-11)!}}

             =\dfrac{\dfrac{7!}{3!\cdot 4!}\times \dfrac{13!}{8!\cdot 5!}}{\dfrac{20!}{11!\cdot 9!}}=0.26818885

<u>2. The 12th package</u>

The probability 12th package is damaged too is 7 - 3 = 4, out of 20 - 11 = 9:

<u>3. Finally</u>

The probability that exactly 12 packages are inspected to find exactly 4 damaged packages is the product of the two calculated probabilities:

         0.26818885\times 4/9=0.119

6 0
4 years ago
30 POINTS PLEASE HELP!!
Sedbober [7]

A polynomial p is graphed. What could be the equation of p?

3 0
4 years ago
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