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2 years ago

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The difference of 1/2 of one number and 2/3 of another number is equal to 2. If the first number were to decrease by 5/6 of it,

and the second number were to increase by 1/6 of it, their sum would be equal to 59. Find the two numbers.
PLZ explain too.

1 answer:

Cerrena [4.2K]2 years ago

5 0

One of the numbers is 60

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What of the following mathematical statements fits the sentence: w decreased by 5?

finlep [7]

The answer is C, w - 5.

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2 years ago

Percentage of number: <br> 70% of 44

Elena L [17]

0.7 * 44 = 30
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2 years ago

Read 2 more answers

The perimeter of a swimmingpool is 78 feet. The difference between four times the length and the width is 73.5 feet. What are th

Marianna [84]

Answer:

Length is 22.5 ft

Width is 16.5 ft

Step-by-step explanation:

4L-w=73.5

4L=73.5+w

L=(73.5+w)/4

P=78

P=2L+2w

78=2[(73.5+w)/4]+2w

78=(73.5+w)/2+2w

78=(73.5+w+4w)/2

2•78=73.5+5w

156=73.5+5w

156-73.5=5w

82.5=5w

82.5/5=w

16.5=w

L=(73.5+w)/4

=(73.5+16.5)/4

=90/4

L=22.5

3 0

3 years ago

Can someone plz help me doing this :D

Mars2501 [29]

Ok so the first thing you would do is input the number where The variables are in the equation so 8^2-5(4)/4

6 0

3 years ago

A sample of Iron-59 contains 50 mg. One hundred days later, the sample contains 10.75 mg. What is the half-life of iron-59, in d

exis [7]

Answer:

$t_{1/2}=45.09 d$

Step-by-step explanation:

We can use the decay equation:

$M=M_{0}e^{-\lambda t}$

M(0) is the initial mass
M is the mass after t (1000 days) time
λ is the decay constant

But:

$\lambda = ln(2)/t_{1/2}$

t(1/2) is the half-life.

So, we can rewrite the initial equation:

$M=M_{0}e^{-\frac{ln(2)}{t_{1/2}}t}$

Now, we just need to solve it for t(1/2):

$ln(\frac{M}{M_{0}})=-\frac{ln(2)}{t_{1/2}}t$

$t_{1/2}=-\frac{ln(2)}{ln(\frac{M}{M_{0}})}t$

$t_{1/2}=-\frac{ln(2)}{ln(\frac{10.75}{50})}100$

$t_{1/2}=45.09 d$

I hope it helps you!

5 0

2 years ago