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3 years ago

13 Solve the inequality n+7<5n-8

Mathematics

1 answer:

Papessa [141]3 years ago

3 0

Answer:

3.75 < n

Step-by-step explanation:

n + 7 < 5n - 8

Add 8 to both sides

n + 7 + 8 < 5n

n + 15 < 5n

Subtract 'n' from both sides

15 < 5n - n

15 < 4n

Divide both sides by 4

$\frac{15}{4}$ < n

3.75 < n

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Inez waters her plants every two days. She trims them every 15 days. She did both today. When will she do them both again?

shtirl [24]

The answer is 30 days.

The solution for this is to find the least common multiple. By getting the multiple of both numbers.

Multiples of 2: 2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40…..

Multiples of 15: 15,30,45,60,75……..

The Least Common Multiples of 2 and 15 is 30. So, Inez will do them both again in 30 days.

The least common multiple (LCM) of two numbers is the smallest number that is multiple by the both number.

7 0

3 years ago

Kyle's phone bill is $40 per month. How much does he have to pay for half a year of phone service? *

Diano4ka-milaya [45]

Answer:

$240

Step-by-step explanation:

40*6=240

8 0

3 years ago

Read 2 more answers

Maths help PLZZ!!!

Slav-nsk [51]

Triangle ABC is an isosceles triangle.

Solution:

Given data:

∠ABC = 70° and ∠ACD = 55°

If two parallel lines are cut by a transversal, then alternate interior angles are congruent.

m∠BAC = m∠ACD

m∠BAC = 55°

Sum of the angles in a straight line add up to 180°.

m∠ACD + m∠ACB + m∠ABC = 180°

55° + m∠ACB + 70° = 180°

m∠ACB + 125° = 180°

Subtract 125° from both sides, we get

m∠ACB = 55°

In triangle ABC,

∠BAC = 55° and ∠ACB = 55°

∠BAC = ∠ACB

Two angles in the triangle are equal.

Therefor triangle ABC is an isosceles triangle.

6 0

3 years ago

Can someone help me?

Pani-rosa [81]

Answer: m=−3

Step-by-step explanation: −40−2(3m+1/2)=7m−2

−40+(−2)(3m)+(−2)(1/2)=7m+−2

−40+−6m+−1=7m+−2

(−6m)+(−40+−1)=7m−2

−6m+−41=7m−2

−6m−41−7m=7m−2−7m

−13m−41+41=−2+41

−13m/−13=39/−13

m=−3

What mistake I guess Keith did make is he subtracted 2 from -39 which equaled to -37 which caused him divide -37 by 13 when it should have been 39 divided by 13 because he should have left 39 alone and not have subtracted 2 from it also it should not have been negative basically what I'm trying to say is that he did his division and subtraction wrong.

5 0

2 years ago

Read 2 more answers

Find sinϴ and cosϴ if tanϴ=1/4 and sinϴ>0

eduard

If you're using the app, try seeing this answer through your browser: brainly.com/question/2787701

_______________

$\mathsf{tan\,\theta=\dfrac{1}{4}\qquad\qquad(sin\,\theta\ \textgreater \ 0)}\\\\\\
\mathsf{\dfrac{sin\,\theta}{cos\,\theta}=\dfrac{1}{4}}\\\\\\
\mathsf{4\,sin\,\theta=cos\,\theta\qquad\quad(i)}$

Square both sides:

$\mathsf{(4\,sin\,\theta)^2=(cos\,\theta)^2}\\\\
\mathsf{4^2\,sin^2\,\theta=cos^2\,\theta}\\\\
\mathsf{16\,sin^2\,\theta=cos^2\,\theta\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\
\mathsf{16\,sin^2\,\theta=1-sin^2\,\theta}$

$\mathsf{16\,sin^2\,\theta+sin^2\,\theta=1}\\\\
\mathsf{17\,sin^2\,\theta=1}\\\\
\mathsf{sin^2\,\theta=\dfrac{1}{17}}\\\\\\
\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{1}{17}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\dfrac{1}{\sqrt{17}}}$

Since $\mathsf{sin\,\theta}$ is positive, you can discard the negative sign. So,

$\mathsf{sin\,\theta=\dfrac{1}{\sqrt{17}}\qquad\quad\checkmark}$

Substitute this value back into $\mathsf{(i)}$ to find $\mathsf{cos\,\theta:}$

$\mathsf{4\cdot \dfrac{1}{\sqrt{17}}=cos\,\theta}\\\\\\
\mathsf{cos\,\theta=\dfrac{4}{\sqrt{17}}\qquad\quad\checkmark}$

I hope this helps. =)

Tags: trigonometric identity relation trig sine cosine tangent sin cos tan trigonometry precalculus

7 0

3 years ago

13 Solve the inequality n+7<5n-8​

13 Solve the inequality n+7<5n-8