The graph of a 4th-degree polynomial is shown. How many real zeros does this function have?
2 answers:
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Answer:
f'(x) = -1/(1 - Cos(x))
Step-by-step explanation:
The quotient rule for derivation is:
For f(x) = h(x)/k(x)
In this case, the function is:
f(x) = Sin(x)/(1 + Cos(x))
Then we have:
h(x) = Sin(x)
h'(x) = Cos(x)
And for the denominator:
k(x) = 1 - Cos(x)
k'(x) = -( -Sin(x)) = Sin(x)
Replacing these in the rule, we get:
Now we can simplify that:
And we know that:
cos^2(x) + sin^2(x) = 1
then:
Answer:
Step-by-step explanation:
