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Tasya [4]
3 years ago
7

The graph of a 4th-degree polynomial is shown. How many real zeros does this function have?

Mathematics
2 answers:
Neporo4naja [7]3 years ago
6 0

Answer:

C:  3

Step-by-step explanation:

The graph touches or crosses the x-axis in 3 places; thus, there are 3 real zeros.

Ymorist [56]3 years ago
3 0
I think 4 and don’t click on any links plz and thank you hope this is right and this helps
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Explain how to solve 5^(x − 2) = 8 using the change of base formula log base b of y equals log y over log b.
Ray Of Light [21]

Answer:

x = 3.3

Step-by-step explanation:

A equation is given to us and we need to solve out for x. The given equation is ,

Take log on both sides with base as " 10" . We have ,

Simplify using the property of log ,  , we have ,

Simplify ,

Again simplify using the property of log ,

We know that log 5 = 0.69 and log 2 = 0.301 , on substituting this , we have ,

Simplify the RHS ,

Add 2 both sides ,

Hence the Value of x is 3.30 .

3 0
2 years ago
If using the method of completing the square to solve the quadratic equation x^2-4x+10=0,which number would have to be added to
chubhunter [2.5K]

Answer:

4

Step-by-step explanation:

Given

x² - 4x + 10 = 0

subtract 10 from both sides

x² - 4x = - 10

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- 2)x + 4 = - 10 + 4

(x - 2)² = - 6

To complete the square add 4

5 0
3 years ago
PLS I NEED HELP ANSWER WILL GIVE BRAINLIEST ANSWER BOTH QUESTIONS ONE AND TWO
KiRa [710]
I hope this is helpful

8 0
3 years ago
Jerald jumped from a bungee tower. If the equation that models his height, in feet, is h = –16t2 + 729, where t is the time in s
Snezhnost [94]

Answer. First option: t > 6.25


Solution:

Height (in feet): h=-16t^2+729

For which interval of time is h less than 104 feet above the ground?

h < 104

Replacing h for -16t^2+729

-16t^2+729 < 104

Solving for h: Subtracting 729 both sides of the inequality:

-16t^2+729-729 < 104-729

-16t^2 < -625

Multiplying the inequality by -1:

(-1)(-16t^2 < -625)

16t^2 > 625

Dividing both sides of the inequality by 16:

16t^2/16 > 625/16

t^2 > 39.0625

Replacing t^2 by [ Absolute value (t) ]^2:

[ Absolute value (t) ]^2 > 39.0625

Square root both sides of the inequality:

sqrt { [ Absolute value (t) ]^2 } > sqrt (39.0625)

Absolute value (t) > 6.25

t < -6.25 or t > 6.25, but t can not be negative, then the solution is:

t > 6.25



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3 years ago
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