Anyone knows how to get free coursehero

Mathematics

2 answers:

LenaWriter [7]2 years ago

3 0

Answer:

nope

Step-by-step explanation:

RideAnS [48]2 years ago

3 0

Answer:

uh no

Step-by-step explanation:

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what is the equation of a line that passes through the point (6,1) and is perpendicular to the line whose equation is y=2x-6?

alexandr402 [8]

Answer:

y = -(1/2)x + 4

Step-by-step explanation:

Use the standard form on an equation: y = mx + b

A line that is perpendicular has a slope that is the opposite reciprocal of the other line. We also have a point (x, y) that is on the line, so our equation begins as..

1 = -(1/2)(6) + b We must solve for b ( -1/2 is the opposite reciprocal of 2)

1 = -3 + b

4 = b

so our equation is

y = -(1/2)x + 4

3 0

3 years ago

Read 2 more answers

0.85 km/s = ___ m/min

Lelechka [254]

To convert km/s to m/min, multiply by 1000*60=60000

hence 0.85km/s=51000 m/min

5 0

3 years ago

A surveyor leaves her base camp and drives 42km on a bearing of 032degree she then drives 28km on a bearing of 154degree,how far

ValentinkaMS [17]

Answer:

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

Step-by-step explanation:

The final position of the surveyor is represented by the following vectorial sum:

$\vec r = \vec r_{1} + \vec r_{2} + \vec r_{3}$ (1)

And this formula is expanded by definition of vectors in rectangular and polar form:

$(x,y) = r_{1}\cdot (\cos \theta_{1}, \sin \theta_{1}) + r_{2}\cdot (\cos \theta_{2}, \sin \theta_{2})$ (1b)

Where:

$x, y$ - Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.

$r_{1}, r_{2}$ - Length of each vector, in kilometers.

$\theta_{1}, \theta_{2}$ - Bearing of each vector in standard position, in sexagesimal degrees.

If we know that $r_{1} = 42\,km$ , $r_{2} = 28\,km$ , $\theta_{1} = 32^{\circ}$ and $\theta_{2} = 154^{\circ}$ , then the resulting coordinates of the final position of the surveyor is: