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ki77a [65]
3 years ago
8

On

Mathematics
1 answer:
Arturiano [62]3 years ago
8 0
Main light or also known as key light. The strongest
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CAN SOMEONE JUST CHECK MY ANSWER?
12345 [234]

Answer:

you are absolutely correct .........

6 0
3 years ago
The point (-3/5,y) in the third quadrant corresponds to angle θ on the unit circle.
romanna [79]
Sec(theta) = 1 / cos (theta) = hypotenuse / x -coordinate

hypotenuse = 1 (because it is the radius of the unit circle)

sec (theta) = 1 / (-3/5) = - 5/3

cot (theta) = 1 / tan(theta) = x-coordinate / y - coordinate

cot (theta) = -3/5 / y

y^2 + (-3/5)^2 = 1 => y^2 = 1 - 9/25 = 16/25 = y = +/- 4/5

Third quadrant => y = -4/5

=> cot (theta) = (-3/5) / (-4/5) = 3/4
7 0
3 years ago
A+3 1/4+5 2/9 what is the value of a, explain how you got the answer
larisa86 [58]

Answer:

a+305/36

Step-by-step explanation:

Convert

3

1

4

3

1

4

to an improper fraction.

a

+

13

4

+

5

2

9

a

+

13

4

+

5

2

9

Convert

5

2

9

5

2

9

to an improper fraction.

a

+

13

4

+

47

9

a

+

13

4

+

47

9

To write

13

4

13

4

as a fraction with a common denominator, multiply by

9

9

9

9

.

a

+

13

4

⋅

9

9

+

47

9

a

+

13

4

⋅

9

9

+

47

9

To write

47

9

47

9

as a fraction with a common denominator, multiply by

4

4

4

4

.

a

+

13

4

⋅

9

9

+

47

9

⋅

4

4

a

+

13

4

⋅

9

9

+

47

9

⋅

4

4

Write each expression with a common denominator of

36

36

, by multiplying each by an appropriate factor of

1

1

.

a

+

13

⋅

9

36

+

47

⋅

4

36

a

+

13

⋅

9

36

+

47

⋅

4

36

Combine the numerators over the common denominator.

a

+

13

⋅

9

+

47

⋅

4

36

a

+

13

⋅

9

+

47

⋅

4

36

Simplify the numerator.

a

+

305

36

a

+

305

36

3 0
3 years ago
Read 2 more answers
Use the functions to find x
suter [353]

Answer:

x = 14

Step-by-step explanation:

f(x) = 10 -  \frac{9}{2} x \\  \\ plug \: f(x) =  - 53 \\  \\  - 53 = 10 -  \frac{9}{2} x \\  \\ \frac{9}{2} x  = 10 + 53 \\  \\ \frac{9}{2} x  = 63 \\  \\ x = 63 \times  \frac{2}{9}  \\  \\ x = 7 \times 2 \\  \\ x = 14

5 0
4 years ago
How does the graph of y=ax^2+c compare to a graph off y=ax^2?
DENIUS [597]
Shifting a graph up by c units involves adding c to the whole function

therefor
y=ax^2+c is c units higher than y=ax^2 (aka, it is shifted c units up)
3 0
4 years ago
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