9514 1404 393
Answer:
x = 10·cos(θ) -4·cot(θ)
Step-by-step explanation:
Apparently, we are to assume that the horizontal lines are parallel to each other.
The relevant trig relations are ...
Sin = Opposite/Hypotenuse
Cos = Adjacent/Hypotenuse
If the junction point in the middle of AB is labeled X, then we have ...
sin(θ) = 4/BX ⇒ BX = 4/sin(θ)
cos(θ) = x/XA ⇒ XA = x/cos(θ)
Then ...
BX +XA = AB = 10
Substituting for BX and XA using the above relations, we get
4/sin(θ) +x/cos(θ) = 10
Solving for x gives ...
x = (10 -4/sin(θ))·cos(θ)
x = 10·cos(θ) -4·cot(θ) . . . . . simplify
_____
We used the identity ...
cot(θ) = cos(θ)/sin(θ)
The answer in this question is A, D and E, we might conclude if a random sample of 36 time interval between eruption has a mean longer that 104 minutes, I can conclude that the population means may be greater than 91 and the probability mean must be more that 91, since the probability is low and also the population mean is 91, and this is an example of a typical sampling result.
Answer:
See below.
Step-by-step explanation:
a.
O is the origin, so its abscissa is 0. O: 0
The only point 4 units from O is A, so A: 4
Point C has a positive abscissa like A.
Points B and C have opposite abscissas. The only opposites are -3 and 3, but C is positive, and B is negative.
B: -3
C: 3
D: -4.5
E: -6
M = (4 + (-6))/2 = -1. M: -1
b.
OB = |0 - (-3)| = |3| = 3
DA = |-4.5 - 4| = |-8.5| = 8.5
The answer to your problem is 189,728
5x+2-x=9
-2 -2
5x-x=7
4x=7
--- ---
4 4
X= 1.75