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2 years ago

What is 10 / 7 minus -3/8

Mathematics

1 answer:

IRISSAK [1]2 years ago

4 0

Answer:

101/56 or 1.803571429

Step-by-step explanation:

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F(5)=-3x+10 what will the domain and range be

Vladimir [108]

F= -3/5 x+2. Hope this helps

3 0

2 years ago

A bullet is fired straight up from a gun with initial velocity 1120 feet per second at an initial height of 8 feet. Use the form

Dafna1 [17]

Answer:

70 seconds

Step-by-step explanation:

Given that;

The initial velocity $v_o$ of the bullet fired = 1120 ft/s

Initial height h = 8 feet

The expression to determine how many seconds it takes the bullet to hit the ground is:

$h = -16t^2 +v_ot + 8$

Thus;

Replacing the value of $v_o$ = 1120 and h = 0 (i.e. when h =0) in the above expression; we have:

$0= -16t^2 +(1120)t + 8$

$= -16t^2 +(1120)t + (8-0)$

= -16t² + 1120t + 8

mulitiply through by (-)

= 16t² -1120t - 8

Divide through by 8

= 2t² - 140t - 1

The above expression forms a quadratic equation.

where;

a = 2

b = -140

c = - 1

So, by using the quadratic formula $\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$ , we have:

$= \dfrac{-(-140) \pm \sqrt{(-140)^2-4(2)(-1)}}{2(2)}$

$= \dfrac{140 \pm \sqrt{19600-(-8)}}{4}$

$= \dfrac{140 \pm \sqrt{19608}}{4}$

$= \dfrac{140 \pm 140}{4}$

$=\dfrac{140+ 140}{4} \ \ \ OR \ \ \ \dfrac{140-140}{4}$

$=\dfrac{280}{4} \ \ \ OR \ \ \ 0$

= 70

Thus, the time (in seconds) it took the bullet to it the ground = 70 seconds

6 0

2 years ago

Henry has 20 Lawns mowed out of a total of 50 lawns. What percentage of the lawns does Henry have to still mow?

elena55 [62]

Henry has completed 40% of his work, leaving him with a remaining 60%.

What you do is divide 20 by 50 and your answer is .4, move the decimal two places to the right to get your percent, 40. Then subtract it out of 100 and you get the remaining 60%, which essentially is your answer.

5 0

2 years ago

The points , (−15,1) and , (−7,r) lie on a line with slope 5/4. Find the missing coordinate r. Click image to enlarge

Nadya [2.5K]

The missing coordinate r is 11.

Solution:

Given points are (–15, 1) and (–7, r).

$x_{1}=-15, x_{2}=-7, y_{1}=1 \text { and } y_{2}=7$