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3 years ago

What is the surface area of this present

Mathematics

1 answer:

ZanzabumX [31]3 years ago

7 0

Answer:

2400

Step-by-step explanation:

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Which of the following points would be a solution to this system of linear inequalities?

pychu [463]

Let's plug in both x and y values in the equation and check if the inequality is true...

$\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}$

$(4,1) \\ y \leqslant x + 1 \\ y < - \frac{x}{2} - 1$

Substitute x as 4 and y as 1

$1 \leqslant 4 + 1 \\ 1 < - \frac{4}{2} - 1$

$0 \leqslant 4 + 1 \\ 1 < - 2 - 1$

$0 \leqslant 5 \\ 1 < - 3$

This is not a solution because both are not true, Only one equation is giving true as answer which is not correct!~

$\purple{ \rule{300pt}{3pt}}$

$(0, - 3) \\ y \leqslant x + 1 \\ y < - \frac{x}{2} - 1$

Substitute x as 0 and y as -3

$- 3 \leqslant 0 + 1 \\ - 3 < - \frac{0}{2} - 1$

$- 3 \leqslant 1 \\ - 3 < - 0 - 1$

$- 3 \leqslant 1 \\ - 3 < - 1$

This is a solution because both are true, Both the equations are true which means the ordered pair is a solution!~

Thus, Option B (0,-3) is the correct choice....

6 0

3 years ago

Follow the directions to solve the system of equations by elimination. 8x + 7y = 39 4x – 14y = –68 Multiply the first equation t

Hitman42 [59]

Answer:

The solution is ( 1/2 , 5)

Step-by-step explanation:

∵ 8x + 7y = 39 ⇒ (1)

∵ 4x - 14y = -68 ⇒ (2)

Multiply (1) by 2

16x + 14y = 78 ⇒ (3)

Add (2) and (3)

∴ 20x = 10 ⇒ x = 10 ÷ 20 = 1/2

∴ x = 1/2

By substitute in (1)

8(1/2) + 7y = 39 ⇒ 7y = 39 - 4 = 35 ⇒ y = 35 ÷ 7 = 5

∴ y = 5

∴ The solution is ( 1/2 , 5)

To check:

8(1/2) + 7(5) = 4 + 35 = 39 = R.H.S

4(1/2) - 14(5) = 2 - 70 = -68 = R.H.S

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4 years ago

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If the function y = sin(x) is transformed to y = sin(2x), how does the graph change?

Solnce55 [7]

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Lady_Fox [76]

Answer:

The pythagorean theorem is a^2 + b^2 = c^2

Step-by-step explanation:

Not sure what you're asking! Sorry! :)

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3 years ago

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