Equation of the line that passes through (-2, 8) with a slope of 0, can be written in point-slope form, $y - y_1 = m(x - x_1)$ and also in slope-intercept form, $y = mx + b$ .

Using a point, (-2, 8) and the slope (m), 0, substitute x1 = -2, y1 = 8 and m = 0 in $y - y_1 = m(x - x_1)$ .

Thus:

$y - 8 = 0(x - (-2))$

$y - 8 = 0$

Rewrite in slope-intercept form

$y - 8 + 8 = 0 + 8$ (addition property of equality)

$y = 8$

8 0

3 years ago

2{ 3[9 + 4(7 -5) - 4]} can you guys help me

alexandr402 [8]

The answer is 78

Please see the attached picture for full solution

Hope it helps

Good luck on your assignment

8 0

3 years ago

Read 2 more answers

The ordered pair (x,5) is a solution to the function f(x) = x^2 + 1

torisob [31]

Answer:

x = ± 2

Step-by-step explanation:

Given

f(x) = x² + 1 and (x, 5 ) is a solution then f(x) = 5

Equating the two gives

x² + 1 = 5 ( subtract 1 from both sides )

x² = 4 ( take the square root of both sides )

x = ± $\sqrt{4}$ = ± 2

Thus (- 2, 5) and (2, 5) are solutions

3 0

3 years ago