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2 years ago

Mistaken giving brainliest!!! Tho

Mathematics

2 answers:

vitfil [10]2 years ago

8 0

Answer:

its C

Step-by-step explanation:

;););)

sveticcg [70]2 years ago

3 0

Answer:

Im not sure but i think its C

Step-by-step explanation:

If its wrong im so sorry TvT

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FIRST PERSON WHO ANSWERS THIS CORRECTLY GETS BRAINLIEST

Firdavs [7]

Answer: Im pretty sure it would be 67, find area of each side then add

6 0

2 years ago

Question is below help needed

RoseWind [281]

The common ratio of both the formulas is 3 and 2. The first formula is explicit and the second is the recursive formula.

<h3>What is the recursive rule?</h3>

A rule is defined such that its definition includes itself.

The given sequence is

-2, -6, -18, -54

Common ratio ;

r = -6 / -2 = 3

$a _ n =-2 (3) ^{n-1}$

This given formula is the explicit formula.

The given sequence is

4, 8, 16, 32

Common ratio ;

r = 8 / 4 = 2

$a_n = a_{n-1}.2\\\\a _1 = 4$

This given formula is the recursive formula.

Learn more about the recursive rule and explicit rules here:

brainly.com/question/12620593

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5 0

1 year ago

Find the area of the figure.

Arisa [49]

Answer:

can u clarify bc area is 2 but 4 things is perimiter

Step-by-step explanation:

4 0

2 years ago

Ronald saves 10.00 to buy a new book. The book original price was 15 but it was on sale for 35% off with a 6% sales tax. Does he

Lady bird [3.3K]

$6.89

The book is $10. Minus the 35% discount ($10X0.35=$3.50). So the subtotal is $10-$3.50=$6.50.

Tax is 6%. So 0.06X$6.50=$0.39

The total including tax is $6.50+$0.39=$6.89

3 0

2 years ago

Ex 2.8<br> 3. find the maximum value of y for the curve y=x^5 -3 for -2≤x≤1

harkovskaia [24]

$y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\
y''(0)=20\cdot0^3=0$

The value of the second derivative for $x=0$ is neither positive nor negative, so you can't tell whether this point is a minimum or a maximum. You need to check the values of the first derivative around the point.
But the value of $5x^4$ is always positive for $x\in\mathbb{R}\setminus \{0\}$ . That means at $x=0$ there's neither minimum nor maximum.
The maximum must be then at either of the endpoints of the interval $[-2,1]$ .
The function $y$ is increasing in its entire domain, so the maximum value is at the right endpoint of the interval.

$y_{max}=y(1)=1^5-3=-2$

4 0

3 years ago