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Mandarinka [93]
2 years ago
12

A coin that can turn up either heads (H) or tails (T) is flipped. If a head turns up, a spinner that can land on any of the firs

t 4 positive integers is spun. If a tail turns up, the coin is flipped again. How many different possible outcomes can you have?
Mathematics
2 answers:
Aneli [31]2 years ago
8 0

Answer:

Infinity

Step-by-step explanation:

It is possible for the coin to endlessly fall on tails, so there are infinity different outcomes.

Tell me if I'm wrong :)

arsen [322]2 years ago
3 0

Answer: 5 I think

Step-by-step explanation: heads w each of the 4 numbers and then tails with no numbers from the spinner

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The zeros of function d are -3 and 8. Which expression could be a factor of function d?
marysya [2.9K]
X+3 or x-8
These answers will both work!
8 0
3 years ago
A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a
Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = 2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

W_2 =  \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0
3 years ago
How many square centimeters are in an area of 5.60 in2?
Phantasy [73]

1 square inch = 2.54^2 = 6.4516 square cms

So 5.60 in^2  = 6.60 * 6.4516 =   36.13cm^2 to nearest hundredth

7 0
3 years ago
8. Solve.
trapecia [35]

Answer:

48 assistants

Step-by-step explanation:

If 1 executive has an average of 1.5 assistants, let x represent the number of assistants that are employed if there are 32 executives in the office.

Thus:

1.5 assistants to 1 executive = x assistants to 32 executives

1.5 : 1 = x : 32

\frac{1.5}{1} = \frac{x}{32}

Cross multiply

1.5*32 = x*1

48 = x

Therefore, 48 assistants were employed in the office.

3 0
3 years ago
Please help with this question.
Lesechka [4]
The answer to your algerbra question is eight over y
4 0
4 years ago
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