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arsen [322]
4 years ago
14

Factored form of 2x^2+x-3​

Mathematics
2 answers:
solniwko [45]4 years ago
5 0

Answer:

The factored form ⇒ (2x + 3)(x - 1)

Step-by-step explanation:

2x² + x - 3 = (2x + 3)(x - 1)

2x² = 2x ×  x

-3    = 3  ×  -1

First bracket is (2x + 3)

Second bracket is (x - 1)

Check Answer:

(2x + 3)(x - 1) = 2x² - 2x + 3x - 3 = 2x² + x - 3

murzikaleks [220]4 years ago
5 0

The correct answer is(2times and plz 3)(x-1)

Step by step explanation

(2*+3)(x-1)= two times to the power of 2-2 times +3 times minus three equals Two times to the power of 2+ X -3

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For i≥1 , let Xi∼G1/2 be distributed Geometrically with parameter 1/2 . Define Yn=1n−−√∑i=1n(Xi−2) Approximate P(−1≤Yn≤2) with l
murzikaleks [220]

Answer:

The answer is "0.68".

Step-by-step explanation:

Given value:

X_i \sim \frac{G_1}{2}

E(X_i)=2 \\

Var (X_i)= \frac{1- \frac{1}{2}}{(\frac{1}{2})^2}\\

             = \frac{ \frac{2-1}{2}}{\frac{1}{4}}\\\\= \frac{ \frac{1}{2}}{\frac{1}{4}}\\\\= \frac{1}{2} \times \frac{4}{1}\\\\= \frac{4}{2}\\\\=2

Now we calculate the \bar X \sim N(2, \sqrt{\frac{2}{n}})\\

\to \frac{\bar X - 2}{\sqrt{\frac{2}{n}}}  \sim  N(0, 1)\\

\to \sum^n_{i=1}  \frac{X_i - 2}{n}  \times\sqrt{\frac{n}{2}}}  \sim  N(0, 1)\\\\\to  \sum^n_{i=1}  \frac{X_i - 2}{\sqrt{2n}}  \sim  N(0, 1)\\

\to Z_n = \frac{1}{\sqrt{n}} \sum^n_{i=1} (X_i -2) \sim N(0, 2)\\

\to P(-1 \leq X_n \leq 2)  = P(Z_n \leq Z) -P(Z_n \leq -1) \\\\

                               = 0.92 -0.24\\\\= 0.68

6 0
3 years ago
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lozanna [386]

Answer:

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Step-by-step explanation:

use a proportion

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x = 1.5

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Step-by-step explanation:

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0.31

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