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coldgirl [10]
3 years ago
6

I have a problem with statistics. What are p-values?

Mathematics
1 answer:
Rashid [163]3 years ago
3 0
A p-value is the probability of getting, in another study, a test statistic that is more extreme than the one obtained in your study if a series of assumptions hold.
You might be interested in
Use the zero product property to find the solutions to the equation x2 – 13x + 30 = 0.
alukav5142 [94]

Answer:

<u>The solutions to this quadratic equation are 10 and 3.</u>

Step-by-step explanation:

1. Let's recall the formula for solving this type of equations, called quadratic equations:

 x = ( - b +/- √ b² - 4ac)/ 2a

The equation given is  x2 – 13x + 30 = 0,

where a = 1, b = - 13 and c = 30

Now replacing with the real values, we have

x = [ - (-13) +/- √ (-13)² - 4 * 1 * 30] / 2 * 1

x = [ 13 +/- √ 169 - 120] / 2

x = [13 +/- √ 49]/ 2

x = [ 13 +/- 7 ]/ 2

<u>x₁ = 13 + 7/2 = 20/2 = 10</u>

<u>x₂ = 13 - 7/2 = 6/2 = 3</u>

8 0
3 years ago
Adar, Chi, and Melissa each left the party by themselves. In how many different orders can they leave?
borishaifa [10]

Answer:

6

Step-by-step explanation:

3*2*1

6 0
2 years ago
Geometry help needed!
lilavasa [31]

Answer:

13.76

Step-by-step explanation:

Area of the whole

The area of the whole = s^2 (the firgure is a square

s = 8

Area of the whole = 8^2 = 64

Area of the unshaded part

The 2 half circles = 1 whole circle

The radius of the 1/2 circle = 4 (eight has been cut in half)

Area of two half circles = 2* (pi r^2/2)

Area of two half circles = 2 * (pi 4^2/2)

area of two half circles =  16*pi

Area of the shaded area

Area of the shaded area = area of the whole - area of the unshaded area

Area of the shaded area = 64 - 16*pi

Area of the shaded area = 64 - 3.14*16 = 13.76

4 0
3 years ago
What is the slope of a line that passes through the points (-3, 2) and (-6, 5)
oksano4ka [1.4K]

Answer:

3/2

Step-by-step explanation:

Y2-Y1

_____

X2-X1

= 5-2

____

-6-(-3)

=3/2

3 0
2 years ago
Read 2 more answers
In Argentina, a cow on a ranch is expected to need an average of 4200 m2
nika2105 [10]

The cows of Argentina needs an approximate area of 4200 m² for grazing, and there is a total of 4500 cows.

And we are asked to find the total area of their grazing but in hectares. So, we can write:

1 \: cow = 4200 \:  {m}^{2}

Then, for 4500 cows:

4500 \: cows = 4200 \:  {m}^{2}  \times 4500

4500 \: cows = 18900000 \: m {}^{2}

We know that, 1 hectares = 10000 m² = 10⁴ m²

Then let the area of the field be x in hectares:

1 \: hectare = 10000 \:  {m}^{2}

x \: hectare = 18900000 \:  {m}^{2}

Then, putting them in proportion, We will get:

x =  \dfrac{18900000}{10000} hectares

x =  \boxed{ 1890 \: hectares}

So, the total area in hectares = <u>1</u><u>8</u><u>9</u><u>0</u><u> </u><u>hectares</u><u>.</u>

And we are done !!

#CarryOnLearning

<u>━━━━━━━━━━━━━━━━━━━━</u>

6 0
3 years ago
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