Answer:
0J
Explanation:
Mass of the lump M1 = 1.0 kg, initial velocity of the lump U1 = 2m/s to the right,
mass of the metal sphere M2 = 0.5kg, initial velocity of the metal sphere M2 = -4m/s to the left. using conservation law of momentum;
M1U1 + M2U2 = V (M1 + M2)
(1.0 × 2) + (0.5 × -4) = V (1 + 0.5)
2 -2 = V (1.5)
0 = V (1.5)
divide both side by 1.5
0/1.5 = V 1.5/1.5
V = 0
since final velocity after sticking together of the two masses equals zero then their combined kinetic energy will also equal to zero
1/2 V(M1 +M2)
1/2 ×0 × 1.5 = 0J
Solution. To check whether the vectors are linearly independent, we must answer the following question: if a linear combination of the vectors is the zero vector, is it necessarily true that all the coefficients are zeros?
Suppose that
x 1 ⃗v 1 + x 2 ⃗v 2 + x 3 ( ⃗v 1 + ⃗v 2 + ⃗v 3 ) = ⃗0
(a linear combination of the vectors is the zero vector). Is it necessarily true that x1 =x2 =x3 =0?
We have
x1⃗v1 + x2⃗v2 + x3(⃗v1 + ⃗v2 + ⃗v3) = x1⃗v1 + x2⃗v2 + x3⃗v1 + x3⃗v2 + x3⃗v3
=(x1 + x3)⃗v1 + (x2 + x3)⃗v2 + x3⃗v3 = ⃗0.
Since ⃗v1, ⃗v2, and ⃗v3 are linearly independent, we must have the coeffi-
cients of the linear combination equal to 0, that is, we must have
x1 + x3 = 0 x2 + x3 = 0 ,
x3 = 0
from which it follows that we must have x1 = x2 = x3 = 0. Hence the
vectors ⃗v1, ⃗v2, and ⃗v1 + ⃗v2 + ⃗v3 are linearly independent.
Answer. The vectors ⃗v1, ⃗v2, and ⃗v1 + ⃗v2 + ⃗v3 are linearly independent.
Answer:
sorry i was late but for anyone else who wants to know the answer is
D. Vygotsky's theory of cognitive development
Explanation:
I think tropical rainforests I could be wrong
Answer:
2.57
Explanation:
Given the data:
X : 17, 17, 16, 17, 23, 22, 21
Mean absolute deviation (MAD) :
Σ|x - xbar| ÷ n
xbar = Σx/ n
n = 7
Σx = (17 + 17 + 16 + 17 + 23 + 22 + 21) = 8
xbar = 133/7 = 19
|x - xbar| :
|17 - 19|= 2
|17 - 19| = 2
|16 - 19| = 3
|17 - 19| = 2
|23 - 19| = 4
|22 - 19| = 3
|21 - 19| = 2
Therefore,
MAD = (2+2+3+2+4+3+2) / 7
MAD = 18 / 7
MAD = 2.57